2. You are on an unknown planet whose mass is 9.2 x 10²kg. It's sun has a mass of 1.4 x 1035 kg, with g = 17.3 m/s². Mplanet = 9.2 x10 x10²ty I 유 Msun = 1.4 x 10³ sky G=17-3m/s2 a) Calculate the orbital radius of the planet.
2. You are on an unknown planet whose mass is 9.2 x 10²kg. It's sun has a mass of 1.4 x 1035 kg, with g = 17.3 m/s². Mplanet = 9.2 x10 x10²ty I 유 Msun = 1.4 x 10³ sky G=17-3m/s2 a) Calculate the orbital radius of the planet.
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Confused on where to start when finding the orbital radius between the two planets. Given : planet mass 9.2 x10^2kg, sun mass 1.4 x10^35kg, and g= 17.3m/s^2
![**Orbital Radius Calculation on an Unknown Planet**
**Problem Statement:**
You are on an unknown planet whose mass is \(9.2 \times 10^{26}\) kg. Its sun has a mass of \(1.4 \times 10^{35}\) kg, with \(g = 17.3 \, \text{m/s}^2\).
**Task:**
a) Calculate the orbital radius of the planet.
**Given Data:**
- Mass of the planet (\(M_{\text{planet}}\)): \(9.2 \times 10^{26}\) kg
- Mass of the sun (\(M_{\text{sun}}\)): \(1.4 \times 10^{35}\) kg
- Gravitational acceleration (\(g\)): \(17.3 \, \text{m/s}^2\)
**Diagram Explanation:**
There is a simple hand-drawn diagram included with this problem. It shows:
- A central object, which represents the sun, depicted with a smiling face and rays extending outward.
- An orbit around the sun marked with a dashed line, indicative of the planet's path.
- A symbol marking the orbital radius (\(R\)) from the planet to the sun along this path.
**Relevant Formula:**
The orbital radius (\(R\)) can be determined using Kepler's third law or modifications thereof, depending on the specific details of the question, including the gravitational constant (G).
Note: The text provided does not explicitly supply the detailed formula for calculation, but in general terms, for an orbital radius:
\[ R = \sqrt{\frac{G \cdot M_{\text{planet}} \cdot M_{\text{sun}}}{g}} \]
Where:
- \(G\) is the universal gravitational constant (\(6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2\)).
### Handwritten Notes in the Image:
- \( M_{\text{planet}} = 9.2 \times 10^{26} \, \text{kg} \)
- \( M_{\text{sun}} = 1.4 \times 10^{35} \, \text{kg} \)
- \( g = 17.3 \, \text{m/s}^2 \)
For precise calculation, further steps would involve solving the specific](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7b47dd07-9dca-411e-981f-312dfe7288cb%2F7f860c9e-a907-4f39-ad18-360565beb4a7%2Ftwfazjd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Orbital Radius Calculation on an Unknown Planet**
**Problem Statement:**
You are on an unknown planet whose mass is \(9.2 \times 10^{26}\) kg. Its sun has a mass of \(1.4 \times 10^{35}\) kg, with \(g = 17.3 \, \text{m/s}^2\).
**Task:**
a) Calculate the orbital radius of the planet.
**Given Data:**
- Mass of the planet (\(M_{\text{planet}}\)): \(9.2 \times 10^{26}\) kg
- Mass of the sun (\(M_{\text{sun}}\)): \(1.4 \times 10^{35}\) kg
- Gravitational acceleration (\(g\)): \(17.3 \, \text{m/s}^2\)
**Diagram Explanation:**
There is a simple hand-drawn diagram included with this problem. It shows:
- A central object, which represents the sun, depicted with a smiling face and rays extending outward.
- An orbit around the sun marked with a dashed line, indicative of the planet's path.
- A symbol marking the orbital radius (\(R\)) from the planet to the sun along this path.
**Relevant Formula:**
The orbital radius (\(R\)) can be determined using Kepler's third law or modifications thereof, depending on the specific details of the question, including the gravitational constant (G).
Note: The text provided does not explicitly supply the detailed formula for calculation, but in general terms, for an orbital radius:
\[ R = \sqrt{\frac{G \cdot M_{\text{planet}} \cdot M_{\text{sun}}}{g}} \]
Where:
- \(G\) is the universal gravitational constant (\(6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2\)).
### Handwritten Notes in the Image:
- \( M_{\text{planet}} = 9.2 \times 10^{26} \, \text{kg} \)
- \( M_{\text{sun}} = 1.4 \times 10^{35} \, \text{kg} \)
- \( g = 17.3 \, \text{m/s}^2 \)
For precise calculation, further steps would involve solving the specific
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