Somewhere far, far away on the other side of our galaxy, there is a new protoplanetary disk where two baby planetesimals are growing. Planetesimal A is currently 5x10° kg, and Planetesimal B is 2x105 kg. If these two planetesimals are 100 meters apart, what is the gravitational force between them? (Hint: the Universal Gravitational Constant (G) is 6.67x10-11 Nm²/kg²) Gm1m2 FG %D r2 Planetesimal B Planetesimal A 2 x 10 kg 5 x 10°kg 100 meters

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### Gravitational Force Between Two Planetesimals

Somewhere far, far away on the other side of our galaxy, there is a new protoplanetary disk where two baby planetesimals are growing. Planetesimal A is currently \(5 \times 10^9\) kg, and Planetesimal B is \(2 \times 10^5\) kg. If these two planetesimals are 100 meters apart, what is the gravitational force between them?

**Hint**: The Universal Gravitational Constant (\( G \)) is \( 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \).

\[
F_G = \frac{G m_1 m_2}{r^2}
\]

#### Diagram Explanation

This diagram depicts two planetesimals, labeled A and B, situated 100 meters apart:

- **Planetesimal A**: Represented by a large blue circle with a mass of \( 5 \times 10^9 \, \text{kg} \).
- **Planetesimal B**: Represented by a smaller green circle with a mass of \( 2 \times 10^5 \, \text{kg} \).
- The distance between Planetesimal A and Planetesimal B is indicated by a horizontal line with the label "100 meters."
- Blue and green arrows point towards each other, indicating the direction of the gravitational force each exerts on the other.

#### Calculation

1. **Mass of Planetesimal A (\( m_1 \))**: \( 5 \times 10^9 \, \text{kg} \)
2. **Mass of Planetesimal B (\( m_2 \))**: \( 2 \times 10^5 \, \text{kg} \)
3. **Distance between the planetesimals (\( r \))**: 100 meters
4. **Universal Gravitational Constant (\( G \))**: \( 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \)

By substituting these values into the gravitational force formula:

\[
F_G = \frac{(6.67 \times 10^{-11}) \times (5 \times 10^9) \times (2
Transcribed Image Text:### Gravitational Force Between Two Planetesimals Somewhere far, far away on the other side of our galaxy, there is a new protoplanetary disk where two baby planetesimals are growing. Planetesimal A is currently \(5 \times 10^9\) kg, and Planetesimal B is \(2 \times 10^5\) kg. If these two planetesimals are 100 meters apart, what is the gravitational force between them? **Hint**: The Universal Gravitational Constant (\( G \)) is \( 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \). \[ F_G = \frac{G m_1 m_2}{r^2} \] #### Diagram Explanation This diagram depicts two planetesimals, labeled A and B, situated 100 meters apart: - **Planetesimal A**: Represented by a large blue circle with a mass of \( 5 \times 10^9 \, \text{kg} \). - **Planetesimal B**: Represented by a smaller green circle with a mass of \( 2 \times 10^5 \, \text{kg} \). - The distance between Planetesimal A and Planetesimal B is indicated by a horizontal line with the label "100 meters." - Blue and green arrows point towards each other, indicating the direction of the gravitational force each exerts on the other. #### Calculation 1. **Mass of Planetesimal A (\( m_1 \))**: \( 5 \times 10^9 \, \text{kg} \) 2. **Mass of Planetesimal B (\( m_2 \))**: \( 2 \times 10^5 \, \text{kg} \) 3. **Distance between the planetesimals (\( r \))**: 100 meters 4. **Universal Gravitational Constant (\( G \))**: \( 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \) By substituting these values into the gravitational force formula: \[ F_G = \frac{(6.67 \times 10^{-11}) \times (5 \times 10^9) \times (2
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