If we treat the mass of Earth as 1, and the radius of Earth as 1, the escape velocity of a planet with 4 times the mass of Earth and the same radius will be: 1) 1. 4 times greater 2) 2 times greater 3) 4 times greater 4) 0.5 times greater
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- Assume the earth's mass is 85.47 x 1025 kg, and radius is 51.93 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.Let’s imagine that you have an idea for an experiment to fly on NASA’s “Vomit Comet.” (What’s special about this plane? It flies in parabolic paths (aka freefall) which result in near weightlessness. This means that you can ignore the effects of gravity when plan your experiment.) You want to mimic the orbital motion of the planets but by using electrostatic force rather than gravitational. And, instead of a planet, you will be orbiting a droplet of water that is 0.5mm in radius and has an deficit of 1.5 x 106 electrons. The droplet is to orbit around a small (1cm radius) sphere. If you want the droplet to move with an orbital radius of 14cm and period of one minute, what should the charge be on the central sphere? BTW The density of water is 997 kg/m3.If the gravitational field strength at the surface of Venus is g, at what distance from the surface of Venus will it be 0.25g? State your answer in terms of the radius of Venus.
- Calculate the surface escape velocities for Mars. rM = 3.3× 106 m, MM = 6 × 1022 kg).The acceleration due to gravity of planet X is 7.80m/s2, and its radius is 5,900 km. The gravitational constant is ?=6.67×10−11m2kg−1s−2. The mass of planet X is close to:What is the magnitude of the gravitational acceleration at a height of two earth radius (2RE) above earth surface? Take gravitational acceleration near Earth surface as 9.81 m/s2. Express your answer in m/s2 and enter numerical value only, no units
- A man is standing on the moon. His mass is 100 kg. The mass of the moon is 7x10^22 kg. The radius is 3.8x10^5 km. How much is the gravitational force between the man and the moon?Assume the earth's mass is 23.335 x 1025 kg, and radius is 76.394 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.Assume the earth's mass is 55.818 x 1025 kg, and radius is 10.63 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.
- Somewhere far, far away on the other side of our galaxy, there is a new protoplanetary disk where two baby planetesimals are growing. Planetesimal A is currently 5x10° kg, and Planetesimal B is 2x105 kg. If these two planetesimals are 100 meters apart, what is the gravitational force between them? (Hint: the Universal Gravitational Constant (G) is 6.67x10-11 Nm²/kg²) Gm,m2 FG r2 Planetesimal A Planetesimal B 5 x 10°kg 2 x 105kg 100 metersGravitational force is F = Gm1m2/r². Set G = 1 and m1 = 1, where m2 will be a planet with 1800 times Earth's mass (so m2 = 1800) and 30 times Earth's radius (so r = 30). What will F be?The International Space Station, which has a mass of 4.94×105 kg, orbits 258 miles above the Earth's surface, and completes one orbit every 94.3 minutes. What is the kinetic energy of the International Space Station in units of GJ (109 Joules)? (Note: don't forget to take into account the radius of the Earth!) Enter answer here GJ