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f(x) = x/x² + 1 efined on the interval [-5, 4]. -) f(x) is concave down on the open interval [-5,0] .) ƒ(x) is concave up on the open interval [0,4] -) The minimum for this function occurs at 0 .) The maximum for this function occurs at 0

f(x) = x/x² + 1 efined on the interval [-5, 4]. -) f(x) is concave down on the open interval [-5,0] .) ƒ(x) is concave up on the open interval [0,4] -) The minimum for this function occurs at 0 .) The maximum for this function occurs at 0

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I got my answer wrong twice. Could any kind tutors help me with this issue?

Answer the following questions for the function

Note: Your answer to parts a and b must be given in interval notation .

 

 

f(x) = xvx? + 1 defined on the interval -5, 4|. a.) f(x) is concave down on the open interval [-5,0] b.) f(x) is concave up on the open interval [0,4] c.) The minimum for this function occurs at 0 d.) The maximum for this function occurs at 0
Transcribed Image Text:f(x) = xvx? + 1 defined on the interval -5, 4|. a.) f(x) is concave down on the open interval [-5,0] b.) f(x) is concave up on the open interval [0,4] c.) The minimum for this function occurs at 0 d.) The maximum for this function occurs at 0
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