Hi. Can you please help determine whether the function is one-to-one? How can I tell? What do I need to do to determine if this equation is the function is one-to-one?Thank you in advance. The image displays a mathematical equation, specifically a quadratic function in vertex form:\[ y = 4(x + 2)^2 - 6 \]In this equation:- The coefficient $4$ indicates the vertical stretch factor of the parabola.- The expression $(x + 2)$ represents a horizontal shift of the parabola to the left by 2 units.- The constant $-6$ signifies a vertical shift of the parabola downward by 6 units.This equation characterizes the graph of a parabola that opens upwards due to the positive coefficient of the squared term. The vertex of the parabola is located at the point $(-2, -6)$.

A function f(x) i.e. y= f(x) is one -one iff f(x1)= f(x2) implies x1= x2

Answered: y= 4(x+2)-6

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Hi. Can you please help determine whether the function is one-to-one? How can I tell? What do I need to do to determine if this equation is the function is one-to-one?

Thank you in advance.

The image displays a mathematical equation, specifically a quadratic function in vertex form:

\[ y = 4(x + 2)^2 - 6 \]

In this equation:

- The coefficient $4$ indicates the vertical stretch factor of the parabola.
- The expression $(x + 2)$ represents a horizontal shift of the parabola to the left by 2 units.
- The constant $-6$ signifies a vertical shift of the parabola downward by 6 units.

This equation characterizes the graph of a parabola that opens upwards due to the positive coefficient of the squared term. The vertex of the parabola is located at the point $(-2, -6)$.

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