Do each of the following equations represent a function? a. –x+y=10 3 b. y² =x-5

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Question
Do each of the following equations represent a function?
**Determining if Equations Represent a Function**

The following problem explores whether each given equation represents a function. 

a. \(\frac{2}{3}x + y = 10\)

b. \(y^2 = x - 5\)

### Explanation:

- **Equation a:** To determine if \(\frac{2}{3}x + y = 10\) is a function, solve for \(y\):

  \[
  y = 10 - \frac{2}{3}x
  \]

  This is a linear equation in the form \(y = mx + b\), which represents a function because, for each input \(x\), there is exactly one output \(y\).

- **Equation b:** For \(y^2 = x - 5\), solving for \(y\) gives:

  \[
  y = \pm \sqrt{x - 5}
  \]

  This equation does not represent a function because, for some values of \(x\), there can be two different \(y\) values (positive and negative square roots). 

### Graphical Representation:

- **Graph of Equation a:** A straight line, confirming a function relationship (one \(y\) for every \(x\)).

- **Graph of Equation b:** A parabola opening sideways, not representing a function because it fails the vertical line test (a vertical line can intersect the graph at more than one point).
Transcribed Image Text:**Determining if Equations Represent a Function** The following problem explores whether each given equation represents a function. a. \(\frac{2}{3}x + y = 10\) b. \(y^2 = x - 5\) ### Explanation: - **Equation a:** To determine if \(\frac{2}{3}x + y = 10\) is a function, solve for \(y\): \[ y = 10 - \frac{2}{3}x \] This is a linear equation in the form \(y = mx + b\), which represents a function because, for each input \(x\), there is exactly one output \(y\). - **Equation b:** For \(y^2 = x - 5\), solving for \(y\) gives: \[ y = \pm \sqrt{x - 5} \] This equation does not represent a function because, for some values of \(x\), there can be two different \(y\) values (positive and negative square roots). ### Graphical Representation: - **Graph of Equation a:** A straight line, confirming a function relationship (one \(y\) for every \(x\)). - **Graph of Equation b:** A parabola opening sideways, not representing a function because it fails the vertical line test (a vertical line can intersect the graph at more than one point).
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Given that: a. 23x+y=10b. y2=x-5

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