A furnace wall consists of 125 mm wide refractory brick and 125 mm wide insulating firebrick separated by an air gap. The outside wall is covered with 12 mm thickness of plaster. The inner surface of the wall is at 1100 and the room temperature is 25. The heat transfer coefficient form outside wall surface to the air in the rooms is 17 W/m2 K, and the resistance to heat flow of the air gap is 0.16 K/W. the thermal conductivities of refractory brick, insulating firebrick, and plaster are 1.6, 0.3 and 0.14 W/m K, respectively. Calculate The rate of heat loss per unit area of wall surface = 1344.88The temperature at each interface throughout the wallThe temperature at the outside surface of the wallCheck your answer by calculating outside roomOnly require help with step 4 i have calculated the rest.

x2=125×10-3x3=12mm=12×10-3Tf=1100°C Tr=25°Ch1=17W/m2kRa=0.16K/Wka=1.6W/mkkf=0.3W/mkkb=0.14W/mk

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Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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A furnace wall consists of 125 mm wide refractory brick and 125 mm wide insulating firebrick separated by an air gap. The outside wall is covered with 12 mm thickness of plaster. The inner surface of the wall is at 1100 and the room temperature is 25. The heat transfer coefficient form outside wall surface to the air in the rooms is 17 W/m² K, and the resistance to heat flow of the air gap is 0.16 K/W. the thermal conductivities of refractory brick, insulating firebrick, and plaster are 1.6, 0.3 and 0.14 W/m K, respectively. Calculate

The rate of heat loss per unit area of wall surface = 1344.88
The temperature at each interface throughout the wall
The temperature at the outside surface of the wall
Check your answer by calculating outside room

Only require help with step 4 i have calculated the rest.

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