Thermal treatment of a steel cube, of 10 cm side length, L, requires a twostep cooling process. In the first step, the cube at the uniform temperature of 500°C isplaced in air where it is cooled to 250°C. In the second step, it is moved to large oilbath of temperature 20°C where the heat transfer coefficient at all surfacesis the same and equal to h = 50 W m-2 K-1.%3DCalculate the total amount of energy lost by the cube and show that the lumpedcapacitance method can be used to calculate the temperature during the second step ofcooling. Calculate the time necessary to reduce the cube temperature to 50°C.Thermal propertiesDensity = 8000 kg m-3Cp= 480 J kg-1 K-1k = 30 W m-1 K-1.%3D

Given that, Length of cube, L=10 cm,Temperature of cube, Ti=500 °C,Cooling temperature of cube,…

Thermal treatment of a steel cube, of 10 cm side length, L, requires a two step cooling process. In the first step, the cube at the uniform temperature of 500°C is placed in air where it is cooled to 250°C. In the second step, it is moved to large oil bath of temperature 20°C where the heat transfer coefficient at all surfaces is the same and equal to h = 50 W m-2 K-1. Calculate the total amount of energy lost by the cube and show that the lumped capacitance method can be used to calculate the temperature during the second step of cooling. Calculate the time necessary to reduce the cube temperature to 50°C.

Thermal treatment of a steel cube, of 10 cm side length, L, requires a two step cooling process. In the first step, the cube at the uniform temperature of 500°C is placed in air where it is cooled to 250°C. In the second step, it is moved to large oil bath of temperature 20°C where the heat transfer coefficient at all surfaces is the same and equal to h = 50 W m-2 K-1. Calculate the total amount of energy lost by the cube and show that the lumped capacitance method can be used to calculate the temperature during the second step of cooling. Calculate the time necessary to reduce the cube temperature to 50°C.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

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Thermal treatment of a steel cube, of 10 cm side length, L, requires a two
step cooling process. In the first step, the cube at the uniform temperature of 500°C is
placed in air where it is cooled to 250°C. In the second step, it is moved to large oil
bath of temperature 20°C where the heat transfer coefficient at all surfaces
is the same and equal to h = 50 W m-2 K-1.
%3D
Calculate the total amount of energy lost by the cube and show that the lumped
capacitance method can be used to calculate the temperature during the second step of
cooling. Calculate the time necessary to reduce the cube temperature to 50°C.
Thermal properties
Density = 8000 kg m-3
Cp= 480 J kg-1 K-1
k = 30 W m-1 K-1.
%3D

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