Fur color in cats is a codominant trait and is located on the X chromosome. Cats can be black, yellow or calico. A calico cat has black and yellow splotches. In order to be calico, the cat must have an allele for the black color and an allele for the yellow color. Use a Punnett square to show why there are no male calico cats.
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- The shape of a heliodor is an X-linked trait. Male heliodors inherit two X chromosomes, while the females inherit an X and a Y chromosome. The recessive allele codes for the common bell-shape while the dominant phenotype is a round shape . Hudson is a round male and has offspring with Heidi, a bell-shaped female. They already have one daughter, Hannah, who is shaped like her mother. What percentage of their offspring will be carriers for the bell-shape trait? a.0% b.25% c.50% d.75% e.100%The shape of a heliodor is an X-linked trait. Male heliodors inherit two X chromosomes, while the females inherit an X and a Y chromosome. The recessive allele codes for the common bell-shape while the dominant phenotype is a round shape . Hudson is a round male and has offspring with Heidi, a bell-shaped female. They already have one daughter, Hannah, who is shaped like her mother. If their next child is a boy, there is a _____% chance it will be round.In humans brown eye color is dominant to blue eye color. Suppose that your mother is homozygous and your father is heterozygous and you have brown eyes. If you have a child with blue eyes, what are the possible genotypes of both of your parents? Group of answer choices Mother bb; Father bb Mother BB; Father BB Mother BB or bb; Father Bb Mother Bb ; Father Bb
- Assume that black fur is dominant to white fur for cats. When a black cat of an unknown genotype presents itself to you, in order to determine its genotype, you should cross with. a ______ cat, this is because ________.Albinism is the absence of pigment throughout the body. Animals with albinism have white fur and reddish eyes. Albinism is inherited as a recessive trait, so animals with two a alleles have albinism, whereas animals with at least one dominant A allele have normal coloring. Using the Punnett square below, determine the probability of two albino parents (with aa genotypes) producing a child with albinism.In Dalmatians, black spots are dominant to the condition of not having black spots. A black-spotted male whose mother did not have black spots is mated with a female that has no spots. They produce a litter of 6 puppies. Using a Punnett square, predict the number of each phenotype of puppy. Don't forget to define the alleles.
- The ABO blood group in humans is controlled by a single locus with three different alleles. Homozygosity for IA produces type A blood. Homozygosity for IB produces type B blood. Homozygosity for IO produces type O blood. Type AB blood is produced by the genotype IA/IB. IO is recessive to IA and IB; thus, IA/IO gives type A blood and IB/IO gives type B blood. In the United States, the allele frequencies for the ABO alleles are given below. The Rh factor in blood typing also has multiple alleles, but the alleles can be classified into two types, positive and negative. Rh+ is dominant over Rh−. The allele frequencies of these alleles are also indicated below. The MN blood antigen trait is controlled by two codominant alleles at a single locus. Type M individuals are homozygous for the M allele, type MN individuals are heterozygous, and type N individuals are homozygous for the N allele (codominant). In the United States, the allele frequencies for this blood group are also indicated…In a particular mammal, having long whiskers is a SEX-INFLUENCED trait; in FEMALES, long whiskers is dominant to short whiskers, and in MALES, short whiskers is dominant to long whiskers. Use W for the long whiskers allele and W* for the short whiskers allele. You cross a true-breeding FEMALE with long whiskers to a true-breeding MALE with short whiskers. After intercrossing the F1 progeny, which of the following results are expected for the resulting F2 progeny? a) None of these choices b) 3/8 of the F2 progeny will be males with short whiskers. c) All of these choices d) 1/8 of the F2 progeny will be females with short whiskers. e) 3/8 of the F2 progeny will be females with long whiskers. O f) 1/8 of the F2 progeny will be males with long whiskers.In pigeons, the checkered pattern is dependent on a dominant gene C and a plain exterior on the recessive allele c. Red color is controlled by a dominant gene B and brown by the recessive allele b. Diagram completely a cross between homozygous checkered, red birds and plain, brown birds. Summarize the expected F2 results.
- The gene for hair color in rabbits has two alleles brown and white. Brown is dominant over white. Fill in the Punnett's Square of offspring genotypes if one parent is heterozygous and the other is white-haired.A monohybrid cross is a mating where alleles of just one gene are tracked in the offspring. A test cross is a mating in which two parents (P generation) are crossed to give F1 (first filial generation) offspring, and then two F1 parents are crossed to give F2 (second filial generation) offspring. By tracking offspring through two generations, a test cross can reveal patterns of inheritance for particular genes. In a cross between a black and a white guinea pig, all members of the F1 generation are black. The F2 generation is made of ¾ black and ¼ white guinea pigs. Diagram this cross, and list the genotypes and phenotypes for each generation.Spotting in horses is a dominant trait. Cross a homozygous spotted horse with a homozygous solid-colored horse. What are the genotypes and phenotypes of their offspring? Cross two of the offspring from the above cross. What are the genotypes and phenotypes or their offspring? Cross a heterozygous spotted horse with a solid-colored horse. What are the genotypes and phenotypes of their offspring?