From well logging process we got the following records:GR-50, NPHI- 9%, ph- 2.23 gm/cc, At- 70 usec/f, GRmax-150, GRmin-50,TD-120° F, limestone rock, Atma= 47.5 usec/nCalculate: Total porosity, Sonic porosity, density porosity, Vsh., and Rw.Additional information SSP= -50 mv, Rmfe=0.2 ohm.m.IMII- -

Given dataBulk density ρb = 2.23gm/cc∆t = 70μsec/ft∆tma =47.5μsec/ftGRmax = 150GRmin = 50TD =…

From well logging process we got the following records: GR-50, NPHI= 9%, Ph 2.23 gm/c, At- 70 usec/fi, GRmax-150, GRmin-50, TD-120 F, limestone rock, Atma- 47.5 usec/fn Calculate: Total porosity, Sonic porosity, density porosity, Vsh., and Rw. Additional information SSP- -50 mv, Rmfe-0.2 ohm.m.

From well logging process we got the following records: GR-50, NPHI= 9%, Ph 2.23 gm/c, At- 70 usec/fi, GRmax-150, GRmin-50, TD-120 F, limestone rock, Atma- 47.5 usec/fn Calculate: Total porosity, Sonic porosity, density porosity, Vsh., and Rw. Additional information SSP- -50 mv, Rmfe-0.2 ohm.m.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Properties of Fluids

The term fluid represents a type of substance that can easily change its shape under any external pressure/force and can flow. Fluids can acquire any shape in which it is stored and can resist normal stresses but cannot resist shear stress in rest condition. Whenever external shear stress is applied to fluids, it starts to flow. The fluids may be liquid or gas. Example- water, air, etc.

Question

From well logging process we got the following records:
GR-50, NPHI- 9%, ph- 2.23 gm/cc, At- 70 usec/f, GRmax-150, GRmin-50,
TD-120° F, limestone rock, Atma= 47.5 usec/n
Calculate: Total porosity, Sonic porosity, density porosity, Vsh., and Rw.
Additional information SSP= -50 mv, Rmfe=0.2 ohm.m.
IMII- -

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