The cooling rate (in °C/s) at the center of a shaft with diameter d (in mm) is given by the following formula log 10(CR) -1.8024 log 10(d) + 4.0565 %3D and the critical cooling rate (CCR in "C/s) of low alloys steels is given as a function of amount of alloying element (in wt%6) as follow (Mn + Cr+Mo+Ni) 1.6 * log 10(CCR) = 4.3-3.27×C- Find the maximum diameter (in mm) of a shaft to be made of alloy A (such that 100% martensite will be produced after quenching) from the following table is given below: Alloy Weight Percentage (wr%) C. Mn Cr Mo Ni 03 08 05 02 055

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question
The cooling rate (in °C/s) at the center of a shaft with diameter d (in mm) is given by the
following formula
log 10(CR)
-1.8024 log 10(d) + 4.0565
%3D
and the critical cooling rate (CCR in °C/s) of low alloys steels is given as a function of amount of
alloying element (in wt%6) as follow.
log 10(CCR)= 4.3-3.27×C-
(Mn + Cr+Mo+ Ni)
1.6
Find the maximum diameter (in mm) of a shaft to be made of alloy A (such that 100%
martensite will be produced after quenching) from the following table is given below:
Alloy Weight Percentage (wr%)
Mn Cr
Mo Ni
A
03 08 05 02 055
0.4 0.6 1.2
0.3 5
0 36 0.7 15 255
0.4 06 12
0.15 5
0 41 0 85o 5 o 25 o s5
04 0.65 0 75 0 25 p.85
Transcribed Image Text:The cooling rate (in °C/s) at the center of a shaft with diameter d (in mm) is given by the following formula log 10(CR) -1.8024 log 10(d) + 4.0565 %3D and the critical cooling rate (CCR in °C/s) of low alloys steels is given as a function of amount of alloying element (in wt%6) as follow. log 10(CCR)= 4.3-3.27×C- (Mn + Cr+Mo+ Ni) 1.6 Find the maximum diameter (in mm) of a shaft to be made of alloy A (such that 100% martensite will be produced after quenching) from the following table is given below: Alloy Weight Percentage (wr%) Mn Cr Mo Ni A 03 08 05 02 055 0.4 0.6 1.2 0.3 5 0 36 0.7 15 255 0.4 06 12 0.15 5 0 41 0 85o 5 o 25 o s5 04 0.65 0 75 0 25 p.85
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Mechanisms of Heat Transfer
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY