From the given data, shows a sieve analysis of soil samples A and B. Classify the soil according to AASHTO Method. Sieve No. Diameter (mm) Percent Passing (Percent Finer) Soil Sample A Soil Sample B 4 RIC 4.76 100 100 8 2.38 90 100 10 2.00 77 78 20 0.84 59 92 40 0.42 51 84 60 0.25 42 79 100 0.149 35 70 200 0.074 33 63 Characteristics of - 40 fraction LL 46 47 PL 29 24
From the given data, shows a sieve analysis of soil samples A and B. Classify the soil according to AASHTO Method. Sieve No. Diameter (mm) Percent Passing (Percent Finer) Soil Sample A Soil Sample B 4 RIC 4.76 100 100 8 2.38 90 100 10 2.00 77 78 20 0.84 59 92 40 0.42 51 84 60 0.25 42 79 100 0.149 35 70 200 0.074 33 63 Characteristics of - 40 fraction LL 46 47 PL 29 24
Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Braja M. Das, Khaled Sobhan
Chapter2: Origin Of Soil And Grain Size
Section: Chapter Questions
Problem 2.2CTP: Refer to Problem 2.C.1. Results of the sieve analysis for Soils A, B, and C are given below. To...
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![EXAMPLE #2:
The table below shows the laboratory results of the sieve analysis of a sample. The soil has a liquid
limit of 35% and plastic limit of 26%. Classify the soil according to AASHTO.
Cumulative
Total mass retained - Cumulative mass retained
Percent
Percent Passing =
x 100%
Mass Retained Mass Retained
Above Each
Sieve
Diameter (mm)
Total mass retained
Passing
(Percent Finer)
Sieve No.
(grams)
4.76
18.96
18.96
For Seive #4:
4
92%
237 – 18.96
Percent Passing =
x 100% = 92%
8
2.38
33,18 €
52.14
78%
237
10
2.00
45.03
97.17
59%
For Seive #8:
237 - 52.14
20
0.84
54.51
151.68
36%
Percent Passing =
x 100% = 78%
237
40
0.42
42.66
194.34
18%
For Seive #10:
237 – 97.17
206.19
x 100% = 59%
60
0.25
11.85
13%
Percent Passing =
237
100
0.149
4.74
210.93
11%
For SNve #20:
200
0.074
4.74
215.67
9%
237 – 151.68
x 100% = 36%
Percent Passing =
237
PAN
21.33
237
0%
TOTAL=
237](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F60e02ab1-5a32-410e-88b4-1b082b008d9c%2F92088bf5-89de-4561-987c-10f8bb084ffc%2Fn7m3je7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:EXAMPLE #2:
The table below shows the laboratory results of the sieve analysis of a sample. The soil has a liquid
limit of 35% and plastic limit of 26%. Classify the soil according to AASHTO.
Cumulative
Total mass retained - Cumulative mass retained
Percent
Percent Passing =
x 100%
Mass Retained Mass Retained
Above Each
Sieve
Diameter (mm)
Total mass retained
Passing
(Percent Finer)
Sieve No.
(grams)
4.76
18.96
18.96
For Seive #4:
4
92%
237 – 18.96
Percent Passing =
x 100% = 92%
8
2.38
33,18 €
52.14
78%
237
10
2.00
45.03
97.17
59%
For Seive #8:
237 - 52.14
20
0.84
54.51
151.68
36%
Percent Passing =
x 100% = 78%
237
40
0.42
42.66
194.34
18%
For Seive #10:
237 – 97.17
206.19
x 100% = 59%
60
0.25
11.85
13%
Percent Passing =
237
100
0.149
4.74
210.93
11%
For SNve #20:
200
0.074
4.74
215.67
9%
237 – 151.68
x 100% = 36%
Percent Passing =
237
PAN
21.33
237
0%
TOTAL=
237
![From the given data, shows a sieve analysis of soil samples A and B. Classify the soil according to
AASHTO Method.
Sieve No.
Diameter (mm)
Percent Passing (Percent Finer)
Soil Sample A
Soil Sample B
4
RIC
4.76
100
100
8
2.38
90
100
10
2.00
77
78
20
0.84
59
92
40
0.42
51
84
60
0.25
42
79
100
0.149
35
70
200
0.074
33
63
Characteristics of – 40 fraction
LL
46
47
PL
29
24](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F60e02ab1-5a32-410e-88b4-1b082b008d9c%2F92088bf5-89de-4561-987c-10f8bb084ffc%2Fhb94nlq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:From the given data, shows a sieve analysis of soil samples A and B. Classify the soil according to
AASHTO Method.
Sieve No.
Diameter (mm)
Percent Passing (Percent Finer)
Soil Sample A
Soil Sample B
4
RIC
4.76
100
100
8
2.38
90
100
10
2.00
77
78
20
0.84
59
92
40
0.42
51
84
60
0.25
42
79
100
0.149
35
70
200
0.074
33
63
Characteristics of – 40 fraction
LL
46
47
PL
29
24
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