InstructionsFrom the following test results, determine the voltage regulation of a 346 kVA, 2,000V, 3 phase Y alternator, at (a) unity pf . (b)0.8 leading pf (c) 0.71 lagging pfTest results: Full load current at 100A is produced on short circuit by a field excitation of 2,5 A. An emf of 500 V is producedon open-circuit by the same excitation. The armature resistance is 0.8 Q.

Answered: Image /qna-images/answer/72c04fe1-11ff-43ae-9696-99c16fdd60a4.jpg

Answered: From the following test results,…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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A synchronous generator has been synchronized to an infinite grid of 13.8 kV and 60 Hz. The generator prime mover C/C is such that the no-load frequency is 62.5 Hz and the power slope is 1 MW/Hz. The AVR C/C (The reactive power against the terminal voltage C/C) is such that the zero reactive power voltage is 14.6 kV, while the slope is 0.4 MVAR/kV. Calculate: (a) the kVA loading of the generator and its power factor. (b) the settings of the prime mover and AVR such that the generator delivers 3 MW at 0.85 lagging power factor.
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From the following test results, determine the voltage regulation of a 346 kVA, 2,000V, 3 phase Y alternator, at (a) unity pf , (b) 0.8 leading pf (c) 0.71 lagging pf