From the following heats of combustion, CH3OH (l) + 3/2 O2 (g) → CO2 (g) + 2 H2O (l), ΔH = -726.4 KJ/mol C (graphite) + O2 (g) → CO2 (g), ΔH = - 393.5 KJ/mol H2 (g) + ½ O2 (g) → H2O (l), ΔH = - 285.8 KJ/mol Calculate the enthalpy of formation of methanol from its elements: C (graphite) + 2 H2 (g) + ½ O2 (g) → CH3OH (l)
From the following heats of combustion, CH3OH (l) + 3/2 O2 (g) → CO2 (g) + 2 H2O (l), ΔH = -726.4 KJ/mol C (graphite) + O2 (g) → CO2 (g), ΔH = - 393.5 KJ/mol H2 (g) + ½ O2 (g) → H2O (l), ΔH = - 285.8 KJ/mol Calculate the enthalpy of formation of methanol from its elements: C (graphite) + 2 H2 (g) + ½ O2 (g) → CH3OH (l)
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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From the following heats of combustion,
CH3OH (l) + 3/2 O2 (g) → CO2 (g) + 2 H2O (l), ΔH = -726.4 KJ/mol
C (graphite) + O2 (g) → CO2 (g), ΔH = - 393.5 KJ/mol
H2 (g) + ½ O2 (g) → H2O (l), ΔH = - 285.8 KJ/mol
Calculate the enthalpy of formation of methanol from its elements:
C (graphite) + 2 H2 (g) + ½ O2 (g) → CH3OH (l)
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