From the following code, explain how it works and calculate the time complexity def solve_n_queens(n): def is_safe(board, row, col): # Verificar la columna for i in range(row): if board[i][col] == 1: return False # Verificar la diagonal izquierda i, j = row, col while i >= 0 and j >= 0: if board[i][j] == 1: return False i -= 1 j -= 1 # Verificar la diagonal derecha i, j = row, col while i >= 0 and j < n: if board[i][j] == 1: return False i -= 1 j += 1 return True def solve(board, row): if row >= n: solution = [] for r in board: solution.append("".join(['R' if x == 1 else '.' for x in r])) solutions.append(solution) return for col in range(n): if is_safe(board, row, col): board[row][col] = 1 solve(board, row + 1) board[row][col] = 0 solutions = [] board = [[0] * n for _ in range(n)] solve(board, 0) return solutions # Ejemplo de uso: n = 8 solutions = solve_n_queens(n) for sol in solutions: for row in sol: print(row) print()
Control structures
Control structures are block of statements that analyze the value of variables and determine the flow of execution based on those values. When a program is running, the CPU executes the code line by line. After sometime, the program reaches the point where it has to make a decision on whether it has to go to another part of the code or repeat execution of certain part of the code. These results affect the flow of the program's code and these are called control structures.
Switch Statement
The switch statement is a key feature that is used by the programmers a lot in the world of programming and coding, as well as in information technology in general. The switch statement is a selection control mechanism that allows the variable value to change the order of the individual statements in the software execution via search.
From the following code, explain how it works and calculate the time complexity
def solve_n_queens(n):
def is_safe(board, row, col):
# Verificar la columna
for i in range(row):
if board[i][col] == 1:
return False
# Verificar la diagonal izquierda
i, j = row, col
while i >= 0 and j >= 0:
if board[i][j] == 1:
return False
i -= 1
j -= 1
# Verificar la diagonal derecha
i, j = row, col
while i >= 0 and j < n:
if board[i][j] == 1:
return False
i -= 1
j += 1
return True
def solve(board, row):
if row >= n:
solution = []
for r in board:
solution.append("".join(['R' if x == 1 else '.' for x in r]))
solutions.append(solution)
return
for col in range(n):
if is_safe(board, row, col):
board[row][col] = 1
solve(board, row + 1)
board[row][col] = 0
solutions = []
board = [[0] * n for _ in range(n)]
solve(board, 0)
return solutions
# Ejemplo de uso:
n = 8
solutions = solve_n_queens(n)
for sol in solutions:
for row in sol:
print(row)
print()
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