From the diagram, the primary voltage is Vp = 2.10 V and the secondary voltage is Vs = 41.2 V Based on the given voltmeter readings, the number of turns and current through the primary and secondary coil can be found. The relationship is given below N subscript s over N subscript p equals V subscript s over V subscript p equals I subscript p over I subscript . How do they know which voltmeter measures primary voltage and which one measures secondary voltage?
From the diagram, the primary voltage is Vp = 2.10 V and the secondary voltage is Vs = 41.2 V Based on the given voltmeter readings, the number of turns and current through the primary and secondary coil can be found. The relationship is given below N subscript s over N subscript p equals V subscript s over V subscript p equals I subscript p over I subscript . How do they know which voltmeter measures primary voltage and which one measures secondary voltage?
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From the diagram, the primary voltage is Vp = 2.10 V
and the secondary voltage is Vs = 41.2 V
Based on the given voltmeter readings, the number of turns and current through the primary and secondary coil can be found. The relationship is given below N subscript s over N subscript p equals V subscript s over V subscript p equals I subscript p over I subscript .
How do they know which voltmeter measures primary voltage and which one measures secondary voltage?
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