From the data given below show that the simple aggregative method satisfies he time reversal test and circular test. 1996 1997 1998 Items 12 10 10 9. 12 27 15 25 7 18 12 24 30 5 35 9 37 40 16 45 14 13 7 20 8 50 15 43 ABCDE
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A: Given that: Following is the contingency table: A B C Row Total 1 10 35 45 90 2 35 45 55…
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A: The data set are :-X :- 2.17, 2.75, 1.48, 1.87, 1.58Then, We will find the mean and standard…
Q: A researcher wants to know whether an educational video about genetics is effective. This researcher…
A: Given that, A researcher wants to know whether an educational video about genetics is effective.…
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A: Given : n=7 suppose level of significance=α=0.05 Day of week Before After d (difference)…
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A: In this context, the researchers interested to study whether drivers had been drinking alcohol and…
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Q: What type of sampling is being employed in this example? cluster sampling:
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Q: * QuestiorI CompletiUIT Status! 1D 40 50 70 80 100 11D 120 13 140 150 16 17 18 19 20 21 220 23 24 25…
A: Solution: 23. The given data is State the hypotheses. Null hypothesis: That is, the amount of…
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A: The data shows the number of flash drives that were defective and not defective from each shift.
Q: Use software to test the null hypothesis of whether there is a relationship between the two…
A: As per our guidelines we can solve first three subpart and rest can be reposted. Solution-: Given:…
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- A random sample of 15 families representing three different Scandinavian countries has been observed for the number of weekend trips they take per year. Are the differences significant (use p=.05, F(critical) = 3.88)? Use the five step model as a guide and write a sentence or two of interpretation for your results. Sweden Norway Denmark 10 11 7 9 10 5 4 5 2 2 2 0Search the web.... OH cistic Test: Test 2: Ch 4-6 brary ontents n e Resources Success Test 2: Ch 4-6- Personal - Microsoft Edge https://mylab.pearson.com/Student/Player Test.aspx?testid=241931004¢erwin=yes STA 2023 Online SUMMER 2022 (CRN 30322) Type here h ? P(1)= (Round to three decimal places as needed.) 2 > S 4 Assume that a procedure yields a binomial distribution with n=3 trials and a probability of success of p=0.05. Use a binomial probability table to find the probability that the number of successes x is exactly 1. Click on the icon to view the binomial probabilities table. 11:59pm 3 * E 14 $ IO 4 R F fs % B 5 Talv T + 8 H J # 144 ( This test: 61 point(s) possible This question: 3 point(s) possible lovens Louis | 06/30/22 5:02 PM 9 JI K B N M 11 O O O Submit test 87°F P : Next 0 { + 106 [ X A ?he following output from MINITAB presents the results of a hypothesis test for a population mean Test of mu = 32 vs. not = 32 %3D %3D StDev 95% CI 1.477775 (31.745937, 37.674063) 1.833838 Mean SE Mean 54 34.71 10.859387 0.072295 How many degrees of freedom are there? O 53 O 54
- 2/2021 a The dean of a university estimates that the mean number of classroom hours per week for full-time faculty is 11.0. As a member of the student council, you want to test this claim A random sample of the number of classroom hours for elg full-time faculty for one week is shown in the table below. At a= 0 10. can vou reject the dean's claim? Complete parts (a through (d) below. Assume the population is normally distributed. Week 8 Assignment Part Il-Joseph Grovogui 10.2 8.4 12.6 14.9 9.3 6.6 5.4 9.5 (a) Write the claim mathematically and identify Họ and Ha. Which of the following correctly states Ho and H? O A. Ho: H>11.0 O B. Ho: H11.0 Hai H<11.0 (b) Use technology to find the P-value. P = (Round to three decimal places as needed.) (c) Decide whether to reject or fail to reject the null hypothesis. Which of the following is correct? O A. Reject Ho because the P-value is greater than the significance level. O B. Fail to reject Ho because the P-value is less than the significance…You are doing a T-test and get a Standardized Test Statistic (STS) of T = 2.1, with d. f. = 23. Round answers to 4 decimals. Find the P-value for a: a. two tailed test : b. right tailed test : ne a. left tailed test : Submit Question Proctor om • Previous MacBook Air 30 D00 4) F1 F3 F4 F5 F8 F9 F10 # $ & * 4 6 7 W E R Y U S D F G H J K .. ..Data from a recent year showed that 63% of the tens of thousands of applicants to a certain program were accepted. A company that trains applicants claimed that 138 of the 210 students it trained that year were accepted. Assume these trainees were representative of the population of applicants. Has the company demonstrated a real improvement over the average? Compute the test statistic z= What is the p-value P= Would you recommend this company based on what you see here?
- Rangecient of Variaice: 45.31N 6.- The day after Thanksgiving-called Black Friday–is one of the largest shopping days in the United States. A group of researchers conducted interviews with a sample of 38 women shopping on Black Friday to gauge their shopping habits and reported the results in a published paper, in 2011. One question was, "“How many hours do you usually spend shopping on Black Friday?" Data for the 38 shoppers are listed here: 66443 16 4 4 5 6 6 5 5 4 6 5 6 4 5 4 44 7 12 5 86 10 5 8 8 3 38 5 6 10 11. Descriptive statistics for these data are in this table: AExplore Data - Descriptive Statistics Options Which column of data would you like to explore? Summary statistics: Explore Data - Column 4 Variance Std. dev. Std. err. . Median Range Min Max Q1 Q3 Column n Mean Sample Size, ni 38 6.078947 38 6 0789474 7 5881935 2.7546676 044686609 13 3 16 4 7 var4 Meani Nedi an: Midrange: 9.5 6.658987 7.588193 Standard Deviation, s I 2.754668 Mean Absolute Deviation 1.958449 Variance,…Q4) Find the p-value for the table aboveA special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage X¯¯¯1X¯1 = $ 1,077 X¯¯¯2X¯2 = $ 1,800 Sample Std. Dev. s1 = $ 693 s2 = $ 814 Repair Incidents n1 = 16 n2 = 13 Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 90 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 90% confidence interval is from to (b) Repeat part (a), using the assumption of unequal variances with Welch's…
- A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage X¯¯¯1X¯1 = $ 1,153 X¯¯¯2X¯2 = $ 1,751 Sample Std. Dev. s1 = $ 663 s2 = $ 820 Repair Incidents n1 = 16 n2 = 14 Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 99 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 99% confidence interval is from to (b) Repeat part (a), using the assumption of unequal variances with Welch's…A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage x¯1x¯1 = $ 1,101 x¯2x¯2 = $ 1,766 Sample Standard Deviation s1 = $ 696 s2 = $ 838 Repair Incidents n1 = 12 n2 = 9 (a) Construct a 90 percent confidence interval for the true difference of the means assuming equal variances. (Round answers to 3 decimal places. Negative values should be indicated by a minus sign.) (b) Repeat part (a), using the assumption of unequal variances with Welch's formula for d.f. (Round answers to 2 decimal places. Negative values should be indicated by a minus sign.) (d) Construct separate…The test statistic is z = 0.86, the critical value is z = 1.645. This is a________.Select one:a. Left tail testb. A and Bc. Right tail testd. Two tail test
