Fourier Series Harmonics Any periodic function f(t)=f(t+T) can be expressed as a Fourier series of sines and cosines: 00 00 bm f(t)=ao + Σa cos(no ot) + Σb sin(noot) n= n= Where Period T and fundamental frequency @0 satisfy the equation T=27/000 1 Ꭲ a0= f(t) dt T 2 T an= Ꭲ T30 f(t) cos(noot)dt 2 T bn= f(t) sin(noot)dt TJ Laplace Transformation The Unit-Step Function u(t): u(t) <= ㅎ e-st The unit-impulse function (t-to): 8(t-t) <==> 0 8(t) <=>1 for to=0 The Exponential Function eat e¯atu(t) <==> (s+a) The Ramp Function tu(t): == tu(t) <==> -at The function te 'u(t): -at te 'u(t) <==> (s+a) Time Differentiation Theorem dV(t) <==> sV(s) - V(0) dt d2V(t) <==> s²V(s) - SV(0) - V'(0) dt2 In the following circuit: If vs (t) is given as a square waves as shown: If L=2H and R=492, Find i(t)? Vs (t)4 8 Solution: 3 Vs (t) + mi(1) R
Fourier Series Harmonics Any periodic function f(t)=f(t+T) can be expressed as a Fourier series of sines and cosines: 00 00 bm f(t)=ao + Σa cos(no ot) + Σb sin(noot) n= n= Where Period T and fundamental frequency @0 satisfy the equation T=27/000 1 Ꭲ a0= f(t) dt T 2 T an= Ꭲ T30 f(t) cos(noot)dt 2 T bn= f(t) sin(noot)dt TJ Laplace Transformation The Unit-Step Function u(t): u(t) <= ㅎ e-st The unit-impulse function (t-to): 8(t-t) <==> 0 8(t) <=>1 for to=0 The Exponential Function eat e¯atu(t) <==> (s+a) The Ramp Function tu(t): == tu(t) <==> -at The function te 'u(t): -at te 'u(t) <==> (s+a) Time Differentiation Theorem dV(t) <==> sV(s) - V(0) dt d2V(t) <==> s²V(s) - SV(0) - V'(0) dt2 In the following circuit: If vs (t) is given as a square waves as shown: If L=2H and R=492, Find i(t)? Vs (t)4 8 Solution: 3 Vs (t) + mi(1) R
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I need help with this problem and an explanation for the solution described below. (Electric Circuits 2: Fourier Circuit Analysis)

Transcribed Image Text:Fourier Series Harmonics
Any periodic function f(t)=f(t+T) can be expressed
as a Fourier series of sines and cosines:
00
00
bm
f(t)=ao + Σa cos(no ot) + Σb sin(noot)
n=
n=
Where Period T and fundamental frequency @0
satisfy the equation T=27/000
1
Ꭲ
a0=
f(t) dt
T
2
T
an=
Ꭲ
T30
f(t) cos(noot)dt
2
T
bn= f(t) sin(noot)dt
TJ
Laplace Transformation
The Unit-Step Function u(t):
u(t) <=
ㅎ
e-st
The unit-impulse function (t-to):
8(t-t) <==> 0
8(t) <=>1 for to=0
The Exponential Function eat
e¯atu(t) <==>
(s+a)
The Ramp Function tu(t):
==
tu(t) <==>
-at
The function te 'u(t):
-at
te
'u(t) <==>
(s+a)
Time Differentiation Theorem
dV(t)
<==> sV(s) - V(0)
dt
d2V(t)
<==> s²V(s) - SV(0) - V'(0)
dt2

Transcribed Image Text:In the following circuit:
If vs (t) is given as a square waves as shown:
If L=2H and R=492, Find i(t)?
Vs (t)4
8
Solution:
3
Vs (t) +
mi(1)
R
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