Four coat color phenotypes occur in mice, Cream (C), Brown (R), Gray (G) and Black (B). Use the following crosses to determine the dominance sequence of the alleles and indicate the parental genotypes. Cross Parent Phenotype |Offspring Parental Genotypes Gray X Black 10 Gray 2 Black X Cream 5 Black, 5 Brown 3 Brown X Brown 7 Brown, 3 Cream 4 Gray X Brown 5 Gray, 5 Black

Four coat color phenotypes occur in mice, Cream (C), Brown (R), Gray (G) and Black (B). Use the following crosses to determine the dominance sequence of the alleles and indicate the parental genotypes. Cross Parent Phenotype |Offspring Parental Genotypes Gray X Black 10 Gray 2 Black X Cream 5 Black, 5 Brown 3 Brown X Brown 7 Brown, 3 Cream 4 Gray X Brown 5 Gray, 5 Black

Biology (MindTap Course List)

11th Edition

ISBN:9781337392938

Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Publisher:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Chapter11: The Basic Principles Of Heredity

Section: Chapter Questions

Problem 11TYU: Individuals of genotype AaBb were mated to individuals of genotype aabb. One thousand offspring were...

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Purple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口ロ口

In dogs, dark coat color is dominant over albino, andshort hair is dominant over long hair. Assume that theseeffects are caused by two independently assorting genes.Seven crosses were done as shown below, in which D andA stand for the dark and albino phenotypes, respectively,and S and L stand for the short-hair and long-hairphenotypes.Number of progenyParental phenotypes D, S D, L A, S A, La. D, S × D, S 88 31 29 12b. D, S × D, L 19 18 0 0c. D, S × A, S 21 0 20 0d. A, S × A, S 0 0 29 9e. D, L × D, L 0 31 0 11f. D, S × D, S 45 16 0 0g. D, S × D, L 31 30 10 10Write the genotypes of the parents in each cross. Use thesymbols C and c for the dark and albino coat-color allelesand the symbols H and h for the short-hair and long-hairalleles, respectively. Assume parents are homozygousunless there is evidence otherwise.
Please draw a punnett square for this
Pigment in the mouse is produced only when the C allele is present.Individuals of the cc genotype have no color. If color is present,it may be determined by the A and a alleles. AA or Aa resultsin agouti color, whereas aa results in black coats.(a) What F1 and F2 genotypic and phenotypic ratios areobtained from a cross between AACC and aacc mice?(b) In the three crosses shown here between agouti femaleswhose genotypes were unknown and males of the aaccgenotype, what are the genotypes of the female parents foreach of the following phenotypic ratios? (1) 8 agouti (2) 9 agouti (3) 4 agouti8 colorless 10 black 5 black 10 colorless
In cats, coat color is an X-linked trait with incomplete dominance, Yellow coat is caused by the allele XT and black coat by the allele X, A tortoise is caused by the heterozygous condition. What is the correct way to represent the genotype of a cat with a tortoise coat? O XIT), XIt) O XIT), Y O XIT, YIt) O XIt), X(t) (WX O 0.25 Question 7 In cats, coat color is an X-linked trait with incomplete dominance. Yellow coat is caused by the allele XT and black coat by the allele X. A tortoise cc is caused by the heterozygous condition. What is the correct way to represent the genotype of a male cat with a black coat? O X(t) Y O XIT) Y O X(t) X(t) O X(t) Y() *ロー #3 %24 & L. E R D G K L レ prt sc alt alt くト

A is dominant over a and B is dominant over b. Genes A/a and B/b assort independently. The parental cross (P) is between true- breeding (homozygous) strains (AA bb x aa BB). The resulting F1 offspring would be [Select ] A F1 x F1 cross gives the F2 generation. The ratio of phenotypes in the F2 generation can be described as [ Select ] In the phenotypic ratio, what number refers to individuals that are: dominant for both traits? [ Select ] recessive for both traits? [Select ] To what phenotypes do the "3"s in the ratio refer? [ Select ] > >
The trihybrid e+f+g+/efg is test crossed to the triple recessive efg/efg and the following genotypes were obtained in the progeny: efg = 2; efg = 28; e'fg* = 9; e*rg 32; efg 73; e*fg* = 10; ef g* =10; e'fg 2; %3D "The odd gene is The gene order is The gene distance between e-f is The gene distance between f-g is The gene distance between e-g is
In mice, the allele C for colored fur is dominant over the allele c for white fur, and the allele V for normal behavior is dominant over the allele v for waltzing behavior, a form of discoordination. Give the genotypes of the parents in each of the following crosses: (a) Colored, normal mice mated with white, normal mice produced 29 colored, normal and 10 colored, waltzing progeny. (b) Colored, normal mice mated with colored, normal mice produced 38 colored, normal, 15 colored, waltzing, 11 white, normal, and 4 white, waltzing progeny. (c) Colored, normal mice mated with white, waltzing mice produced 8 colored, normal, 7 colored, waltzing, 9 white, normal, and 6 white, waltzing progeny.
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The allele for red flowers (R) and blue flowers (B) show incomplete dominance producing the heterozygote phenotype of purple flowers. Complete Punnett square and answer the questions for the cross between two purple flowers (RB x RB). R В What is the probability of having red flowers? R What is the probability of having purple flowers? B What is the probability of having blue flowers? :: RR : RB : BB :: 0% :: 25% :: 50% :: 75% :: 100%
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The phenotype of spotting in dogs (A) is dominant to no spots (a). When 2 heterozygous spotted dogs are crossed (Aa X Aa), the outcome is shown below: 2/3 Spots 1/3 No Spots What is the best explanation for this outcome, and what are the genotypes of spotted and non-spotted offspring?