**Formation of iodine from iodide.**- Assign oxidation numbers to each atom.- Identify the oxidizing agent and the reducing agent.**Reaction:**\[ 2 \text{I}^- (aq) + \text{MnO}_2(s) + 4 \text{H}^+ (aq) \rightarrow \text{I}_2(s) + \text{Mn}^{2+}(aq) + 2 \text{H}_2\text{O}(l) \]**Explanation:**1. **Oxidation Numbers**: - Iodide (\(\text{I}^-\)) has an oxidation number of -1. - Iodine (\(\text{I}_2\)) has an oxidation number of 0. - Manganese in \(\text{MnO}_2\) has an oxidation number of +4. - Manganese in \(\text{Mn}^{2+}\) has an oxidation number of +2. - Hydrogen (\(\text{H}^+\)) has an oxidation number of +1. - Oxygen in water (\(\text{H}_2\text{O}\)) and in \(\text{MnO}_2\) has an oxidation number of -2.2. **Identifying the Agents**: - **Oxidizing Agent**: MnO\(_2\) (Manganese is reduced from +4 to +2) - **Reducing Agent**: I\(^-\) (Iodide is oxidized from -1 to 0)This reaction illustrates the process of a redox reaction, where iodide ions are oxidized to iodine, and manganese dioxide is reduced to Mn\(^{2+}\) ions.

In the question, we are given an ionic equation for a redox reaction for the formation of iodine from iodide ion in the presence of MnO2 . The equation for the redox reaction is given as- 2 I- (aq) + MnO2 (s) +4 H+ (aq)→ I2 (s) + Mn2+ (aq) + 2 H2O (l)2 I- (aq) + MnO2 (s) +4 H+ (aq)→ I2 (s) + Mn2+ (aq) + 2 H2O (l) From the given reaction equation it is clearly visible that as I- is getting converted to I2 which has an oxidation state of 0, therefore iodide ion is getting oxidized, whereas, MnO2 which has an oxidation state of +4 is getting converted to Mn2+ which is reduction. Therefore the oxidation state of each atom in the equation is given as- 2 I-1 (aq) + Mn+4O2-2 (s) +4 H+1 (aq)→ I20 (s) + Mn2+ (aq) + 2 H2O (l) Anode: 2 I- (aq) → I2 (s) + 2 e- (Oxidation) Cathode: Mn+4 + 2 e- → Mn2+ (Reduction) As the MnO2 is getting reduced, therefore, Oxidizing agent - MnO2 And, as I- is getting oxidized to I2 Reducing agent - I-

Answered: Formation of iodine from iodide. Assign…

Science

Chemistry

Formation of iodine from iodide. Assign oxidation numbers to each atom. Identify the oxidizing agent and the reducing agent.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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