1. Assign oxidation numbers to the atoms in each of the following species: SrBr2, Zn(OH).2, SnH4, Ca(SiO3), Cr2072, Cas(PO4)3F, CsH

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### Oxidation Numbers in Various Chemical Species

#### Problem Statement:
1. Assign oxidation numbers to the atoms in each of the following species:
   - SrBr₂
   - Zn(OH)₄²⁻
   - SnH₄
   - Ca(SiO₃)
   - Cr₂O₇²⁻
   - Ca₅(PO₄)₃F
   - CsH
   
#### Solution Steps:
To assign oxidation numbers, follow these rules:
- The oxidation number of an atom in its elemental form is always zero.
- The oxidation number of a monatomic ion equals the charge of the ion.
- Oxygen usually has an oxidation number of -2 in compounds, except in peroxides where it is -1 and in OF₂ where it is +2.
- Hydrogen generally has an oxidation number of +1 when bonded to non-metals and -1 when bonded to metals.
- The sum of oxidation numbers for all atoms in a neutral molecule must be zero, and for a polyatomic ion, it must be equal to the ion's charge.

#### Applying These Rules:
1. **SrBr₂**
   - Sr typically has an oxidation number of +2.
   - Each Br atom typically has an oxidation number of -1.
   - Hence for SrBr₂: Sr(+2)Br₂(-1 each)

2. **Zn(OH)₄²⁻**
   - Zn typically has an oxidation number of +2.
   - Each OH group will have O with an oxidation number of -2 and H with an oxidation number of +1.
   - Hence for Zn(OH)₄²⁻: Zn(+2)(OH)₄(-1 each from OH group)

3. **SnH₄**
   - H has an oxidation number of -1 when bonded to metals.
   - Hence for SnH₄: Sn(+4)H₄(-1 each)

4. **Ca(SiO₃)**
   - Ca typically has an oxidation number of +2.
   - O is usually -2, making total oxidation numbers of O in SiO₃ equal to -6.
   - Hence Si must be +4 to balance the total charge to zero.
   - Hence for Ca(SiO₃): Ca(+2)Si(+4)O₃(-2 each)

5. **Cr₂
Transcribed Image Text:### Oxidation Numbers in Various Chemical Species #### Problem Statement: 1. Assign oxidation numbers to the atoms in each of the following species: - SrBr₂ - Zn(OH)₄²⁻ - SnH₄ - Ca(SiO₃) - Cr₂O₇²⁻ - Ca₅(PO₄)₃F - CsH #### Solution Steps: To assign oxidation numbers, follow these rules: - The oxidation number of an atom in its elemental form is always zero. - The oxidation number of a monatomic ion equals the charge of the ion. - Oxygen usually has an oxidation number of -2 in compounds, except in peroxides where it is -1 and in OF₂ where it is +2. - Hydrogen generally has an oxidation number of +1 when bonded to non-metals and -1 when bonded to metals. - The sum of oxidation numbers for all atoms in a neutral molecule must be zero, and for a polyatomic ion, it must be equal to the ion's charge. #### Applying These Rules: 1. **SrBr₂** - Sr typically has an oxidation number of +2. - Each Br atom typically has an oxidation number of -1. - Hence for SrBr₂: Sr(+2)Br₂(-1 each) 2. **Zn(OH)₄²⁻** - Zn typically has an oxidation number of +2. - Each OH group will have O with an oxidation number of -2 and H with an oxidation number of +1. - Hence for Zn(OH)₄²⁻: Zn(+2)(OH)₄(-1 each from OH group) 3. **SnH₄** - H has an oxidation number of -1 when bonded to metals. - Hence for SnH₄: Sn(+4)H₄(-1 each) 4. **Ca(SiO₃)** - Ca typically has an oxidation number of +2. - O is usually -2, making total oxidation numbers of O in SiO₃ equal to -6. - Hence Si must be +4 to balance the total charge to zero. - Hence for Ca(SiO₃): Ca(+2)Si(+4)O₃(-2 each) 5. **Cr₂
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