Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:### Oxidation Numbers in Various Chemical Species
#### Problem Statement:
1. Assign oxidation numbers to the atoms in each of the following species:
- SrBr₂
- Zn(OH)₄²⁻
- SnH₄
- Ca(SiO₃)
- Cr₂O₇²⁻
- Ca₅(PO₄)₃F
- CsH
#### Solution Steps:
To assign oxidation numbers, follow these rules:
- The oxidation number of an atom in its elemental form is always zero.
- The oxidation number of a monatomic ion equals the charge of the ion.
- Oxygen usually has an oxidation number of -2 in compounds, except in peroxides where it is -1 and in OF₂ where it is +2.
- Hydrogen generally has an oxidation number of +1 when bonded to non-metals and -1 when bonded to metals.
- The sum of oxidation numbers for all atoms in a neutral molecule must be zero, and for a polyatomic ion, it must be equal to the ion's charge.
#### Applying These Rules:
1. **SrBr₂**
- Sr typically has an oxidation number of +2.
- Each Br atom typically has an oxidation number of -1.
- Hence for SrBr₂: Sr(+2)Br₂(-1 each)
2. **Zn(OH)₄²⁻**
- Zn typically has an oxidation number of +2.
- Each OH group will have O with an oxidation number of -2 and H with an oxidation number of +1.
- Hence for Zn(OH)₄²⁻: Zn(+2)(OH)₄(-1 each from OH group)
3. **SnH₄**
- H has an oxidation number of -1 when bonded to metals.
- Hence for SnH₄: Sn(+4)H₄(-1 each)
4. **Ca(SiO₃)**
- Ca typically has an oxidation number of +2.
- O is usually -2, making total oxidation numbers of O in SiO₃ equal to -6.
- Hence Si must be +4 to balance the total charge to zero.
- Hence for Ca(SiO₃): Ca(+2)Si(+4)O₃(-2 each)
5. **Cr₂
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