formal charges: all of the atoms are 0 formal charges: sulfur and two oxygen atoms are 0, the other two oxygens are each -1 formal charges: sulfur is 0 and the oxygen atoms are each -0.75 because 4*(-0.75)=-3 bond angle: all are 90 degrees because there are 4 groups around sulfur bond angle: all are 109.5 degrees because there are 4 groups around sulfur bond angle: both 90 and 120 degrees because there are 5 bonds to sulfur geometry: tetrahedral geometry: square planar geometry: see saw O SO bond order: the single bonds are 1 and the double bonds are 2 SO bond order: all four bonds are 1.5 O SO bond order: half of the time cach bond is one and the other half of the time cach bond is
formal charges: all of the atoms are 0 formal charges: sulfur and two oxygen atoms are 0, the other two oxygens are each -1 formal charges: sulfur is 0 and the oxygen atoms are each -0.75 because 4*(-0.75)=-3 bond angle: all are 90 degrees because there are 4 groups around sulfur bond angle: all are 109.5 degrees because there are 4 groups around sulfur bond angle: both 90 and 120 degrees because there are 5 bonds to sulfur geometry: tetrahedral geometry: square planar geometry: see saw O SO bond order: the single bonds are 1 and the double bonds are 2 SO bond order: all four bonds are 1.5 O SO bond order: half of the time cach bond is one and the other half of the time cach bond is
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
The best Lewis structure for sulfate is shown here. There are several other equivalent resonance forms of this Lewis structure. Choose from the following all the correct details of sulfate.
Expert Solution
Step 1
In case of SO4^2- many resonating structures can be drawn. But, we can also drawn only two degenerates resonance structures.
F.C. = No. of valence shell electrons - No. of covalent bonds - 2*no. of l.p.
For S atom = 6-6-2*0 = 0
For single bonded O = 6-1-2*3 = -1
For double bonded O = 6-2-2*2 = 0
Hence, the correct statement is : b. Formal charge : S and two O atoms are 0 while the other two O atoms are -1 each.
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