for uniform distributionstatistical Inferencegive me the following (for uniform distribution)1-Biased2-Unbiased3-Sufficiency4-Consistency5-Efficiency6-MVUE7-Confidence interval8-Test hypothesis(i need this property of uniform distribution)1f(x) =for A

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Answered: for uniform distribution statistical…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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What statement is incorrect regarding the z-statistic and the z-critical when taking a sample in order to estimate the Mean of a population? The z-statistic is the z-value determined by subtracting the hypothesis mean from the mean of the sample data and dividing by the standard error The standard error is the standard deviation divided by the square root of the # of sample points z-critical is at the edges of the confidence interval: negative z-critical is the left edge and positive z-critical is the right edge If a positive z-statistic is less than the positive z-critical, we reject the Null hypothesis
A random sample of 25 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 14 and the sample standard deviation is 2. Use a level of significance of 0.05 to conduct a two-tailed test of the claim that the population mean is 13.5. (a) Is it appropriate to use a Student's t distribution? Explain. Yes, because the x distribution is mound-shaped and symmetric and ? is unknown. No, the x distribution is skewed left. No, the x distribution is skewed right. No, the x distribution is not symmetric.No, ? is known. How many degrees of freedom do we use?(b) What are the hypotheses? H0: ? = 13.5; H1: ? < 13.5 H0: ? < 13.5; H1: ? = 13.5 H0: ? = 13.5; H1: ? ≠ 13.5 H0: ? > 13.5; H1: ? = 13.5 H0: ? = 13.5; H1: ? > 13.5 (c) Compute the t value of the sample test statistic. (Round your answer to three decimal places.) t = (d) Estimate the P-value for the test. P-value > 0.250 0.100 < P-value < 0.250 0.050 < P-value < 0.100 0.010…
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random sample of 50 binomial trials resulted in 20 successes. Test the claim that the population proportion of successes does not equal 0.50. Use a level of significance of 0.05. (a) Can a normal distribution be used for the distribution? Explain. No, n·q is greater than 5, but n·p is less than 5.Yes, n·p and n·q are both greater than 5. No, n·p is greater than 5, but n·q is less than 5.No, n·p and n·q are both less than 5.Yes, n·p and n·q are both less than 5. (b) State the hypotheses. H0: p = 0.5; H1: p > 0.5H0: p = 0.5; H1: p ≠ 0.5 H0: p < 0.5; H1: p = 0.5H0: p = 0.5; H1: p < 0.5 (c) Compute . (Enter a number.)p hat = Compute the corresponding standardized sample test statistic. (Enter a number. Round your answer to two decimal places.) (d) Find the P-value of the test statistic. (Enter a number. Round your answer to four decimal places.) (e) Do you reject or fail to reject H0? Explain. At the α = 0.05 level, we reject the null hypothesis and conclude the data…
The Energy Star rating system is an energy efficiency program run by the U.S. Environmental Protection Agency (EPA). Energy Star certified appliances, such as televisions and refrigerators, are rated in regard to their average energy consumption per year. A certain brand of Energy Star certified refrigerator is stated to have a mean yearly electricity cost of $84. A consumer advocacy organization believes that this claim is wrong, that the energy consumption of this particular refrigerator is different than $84 per year. The group collected a random sample of 16 refrigerators of the model in question and had each lab-tested for electricity consumption. The yearly energy consumption of each is given below. 83.48 83.72 84.45 83.54 83.25 84.43 84.93 84.11 84.11 83.71 83.97 84.88 84.31 83.77 84.66 83.1 Using a significance level of 20%, test the hypothesis that the average yearly electricity consumption of the refrigerator in question is different than $84 per year. Assume that the…
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Hello, can you please explain to me of this math problem. Break this math problem down for me to understand . Thank you. Use the standard normal distribution or the t- distribution to construct a 99% confidence interval for the population mean. Justifty your decision if neither distribution can be used explain. Why Intepret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.38. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 1.6, 4.8, 7.2, 4.5, 7.3, 7.3, 5.7, 2.6, 7.4, 1.9, 1.5, 4.3, 7.4, 3.9, 5.6, 3.3, 4.4, 3.5, 2.9, 4.3, 6.6, 2.7, 7.3, 6.9, 7.5 Which distribution should be used to construct the confidence interval? Use a normal distribution because σ is known and the data are normally distributed. Select the correct choice below and, if necessary, fill in any answer boxes to complete your choice. (A). The 99% confidence interval…
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A new system is introduced and 10 hammer samples are drawn. Since the no. of samples is < 30, t-test must have been used. Please correct me if this interpretataion is wrong According to this flowchart, t-test must be used when the sample size is less than 30.

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for uniform distribution statistical Inference give me the following (for uniform distribution) 1-Biased 2-Unbiased 3-Sufficiency 4-Consistency 5-Efficiency 6-MVUE 7-Confidence interval 8-Test hypothesis (i need this property of uniform distribution) 1 f(x) = for A