PLEASE MAKE A NORMAL DISTRIBUTION CURVE FOR THIS. DIGITAL ONLY NOT HANDWRITTEN
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
PLEASE MAKE A
![Given
Mean(µ) = 65.33
standard deviation(6) = 31.59
sample size(n) = 7
Required probability is P x ≥ 50
P(T250)
50-μ
- (²)
= P
= P(₁)
50-65.33
31.59
√7
= P(Z > -1.28)
-1-P(2<-1.28)
Pz≥
= 10.1003
from z table
STANDARD NORMAL DISTRIBUTION: Table Values Represent AREA to the LEFT of the Z score.
.02
.03
.05
.06
.07
.08
.00003
.00005
.00008 .00008
00012 00012
.00024
Z
.00
.01
.04
-3.9 .00005 .00005 .00004 00004
.00004
.00004 .00004 .00004
-3.8 .00007 .00007 .00007 .00006 .00006 .00006 .00006 .00005
-3.7 .00011 .00010 .00010 .00010 .00009 .00009 .00008
-3.6 .00016 .00015 .00015 .00014 .00014 .00013 .00013
-3.5 .00023 .00022 .00022 .00021 .00020 .00019 .00019 00018 00017
-3.4 00034 .00032 .00031 .00030 .00029 .00028 .00027 .00026 .00025
-3.3 00048 .00047 .00045 .00043 .00042 .00040 .00039 .00038 .00036 .00035
-3.2 .00069 .00066 .00064 .00062 .00060 .00058 .00056 .00054 .00052
-3.1 .00097 .00094 .00090
.00087 .00084 .00082
.00079
.00076 .00074
-3.0 .00135 .00131 .00126 .00122 .00118 .00114 .00111 .00107 .00104
-2.9 .00187 .00181 .00175 .00169 .00164 .00159 .00154 .00149 .00144
-2.8 .00256 .00248 .00240 .00233 .00226 .00219 .00212 .00205 .00199
-2.7 .00347 00336 .00326 .00317 .00307 .00298 .00289 .00280 .00272
-2.6 00466 .00453 .00440 .00427
.00402 .00391
-2.5 .00621 00604 .00587 .00570
.00539 .00523
.00695
.00050
.00071
.00100
.00139
.00193
.00264
.00357
.00415
.00554
.00379 .00368
.00508
.00676 .00657
.00494
.00480
.00776
.00755
.00734 .00714
.00639
01017
.00990
.00939
.00914
.00889 .00866
.00842
-2.4 .00820 .00798
-2.3 .01072 .01044
-2.2 01390 .01355
-2.1 .01786
.01743 01700
.01321
01287
.01191
.01160 .01130
.01101
01659
.01539
.01500 01463
.01426
-2.0 02275 .02222
02169
.02118
.01970
.01923 01876
.01831
-1.9 .02872 .02807
.02743
.02680
.02619
.02559 .02500 .02442 02385
02330
-1.8
.03593 .03515
.03438
.03362
.03288
-1.7
04457 .04363
04272
04182 .04093
-1.6
.05480 .05370 05262
.06681 .06552 .06426
-1.5
.03216 .03144 .03074 .03005 .02938
04006
.03920 03836 .03754 .03673
.05155 .05050 .04947 04846 .04746 04648 .04551
.06301 .06178 .06057 .05938 .05821 .05705 05592
08076 .07927 .07780 .07636 .07493 07353 .07215 .07078 06944 .06811
09012 08851 .08691 08534 08379 08226
.10565 .10383 .10204 .10027 09853
-1.4
-1.3 .09680 .09510 .09342
09176
-1.2 .11507 .11314 .11123
.10935
.10749
= 0.8997
P(x ≥ 50) = 0.8997
.00964
01255 .01222
.01618
.02068
.01578
.02018
.09
.00003
.00005
.00008
.00011
.00017](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faec36bf2-f3f0-4133-a0b2-246dadf54ad6%2Fb0a0c149-7241-42e7-93a0-b2cccd116dc7%2F4ohkydr_processed.png&w=3840&q=75)
Transcribed Image Text:Given
Mean(µ) = 65.33
standard deviation(6) = 31.59
sample size(n) = 7
Required probability is P x ≥ 50
P(T250)
50-μ
- (²)
= P
= P(₁)
50-65.33
31.59
√7
= P(Z > -1.28)
-1-P(2<-1.28)
Pz≥
= 10.1003
from z table
STANDARD NORMAL DISTRIBUTION: Table Values Represent AREA to the LEFT of the Z score.
.02
.03
.05
.06
.07
.08
.00003
.00005
.00008 .00008
00012 00012
.00024
Z
.00
.01
.04
-3.9 .00005 .00005 .00004 00004
.00004
.00004 .00004 .00004
-3.8 .00007 .00007 .00007 .00006 .00006 .00006 .00006 .00005
-3.7 .00011 .00010 .00010 .00010 .00009 .00009 .00008
-3.6 .00016 .00015 .00015 .00014 .00014 .00013 .00013
-3.5 .00023 .00022 .00022 .00021 .00020 .00019 .00019 00018 00017
-3.4 00034 .00032 .00031 .00030 .00029 .00028 .00027 .00026 .00025
-3.3 00048 .00047 .00045 .00043 .00042 .00040 .00039 .00038 .00036 .00035
-3.2 .00069 .00066 .00064 .00062 .00060 .00058 .00056 .00054 .00052
-3.1 .00097 .00094 .00090
.00087 .00084 .00082
.00079
.00076 .00074
-3.0 .00135 .00131 .00126 .00122 .00118 .00114 .00111 .00107 .00104
-2.9 .00187 .00181 .00175 .00169 .00164 .00159 .00154 .00149 .00144
-2.8 .00256 .00248 .00240 .00233 .00226 .00219 .00212 .00205 .00199
-2.7 .00347 00336 .00326 .00317 .00307 .00298 .00289 .00280 .00272
-2.6 00466 .00453 .00440 .00427
.00402 .00391
-2.5 .00621 00604 .00587 .00570
.00539 .00523
.00695
.00050
.00071
.00100
.00139
.00193
.00264
.00357
.00415
.00554
.00379 .00368
.00508
.00676 .00657
.00494
.00480
.00776
.00755
.00734 .00714
.00639
01017
.00990
.00939
.00914
.00889 .00866
.00842
-2.4 .00820 .00798
-2.3 .01072 .01044
-2.2 01390 .01355
-2.1 .01786
.01743 01700
.01321
01287
.01191
.01160 .01130
.01101
01659
.01539
.01500 01463
.01426
-2.0 02275 .02222
02169
.02118
.01970
.01923 01876
.01831
-1.9 .02872 .02807
.02743
.02680
.02619
.02559 .02500 .02442 02385
02330
-1.8
.03593 .03515
.03438
.03362
.03288
-1.7
04457 .04363
04272
04182 .04093
-1.6
.05480 .05370 05262
.06681 .06552 .06426
-1.5
.03216 .03144 .03074 .03005 .02938
04006
.03920 03836 .03754 .03673
.05155 .05050 .04947 04846 .04746 04648 .04551
.06301 .06178 .06057 .05938 .05821 .05705 05592
08076 .07927 .07780 .07636 .07493 07353 .07215 .07078 06944 .06811
09012 08851 .08691 08534 08379 08226
.10565 .10383 .10204 .10027 09853
-1.4
-1.3 .09680 .09510 .09342
09176
-1.2 .11507 .11314 .11123
.10935
.10749
= 0.8997
P(x ≥ 50) = 0.8997
.00964
01255 .01222
.01618
.02068
.01578
.02018
.09
.00003
.00005
.00008
.00011
.00017
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