For this question, is this an endothermic or exothermic reaction? I am confused at the part where work is negative and heat is positive, because I thought they were all either pos or neg. thank you.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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For this question, is this an endothermic or exothermic reaction? I am confused at the part where work is negative and heat is positive, because I thought they were all either pos or neg. thank you.

Cnarge inheat
sotemexpands
aheatadded
3. A balloon is inflated to its full extent by(heating, The volume of the balloon changes from
4.0x106 liters to 4.5x10° liters by the addition of 1.3x10 Joules of energy as heat. Calculate
the change in internal energy, AE, for the process (assume the balloon expands at constant
pressure of 1.00 atm). {Hint: R = 0.08206 L·atm/mole-K = 8.3145 J/mole K}
gasconstant
Change inheak
gasconstant
%3D
%3D
for youles
AE = q + w = heat + work
Because heat is added, the internal energy of the system increases and q = +1.3x10 J
%3D
The system expands and does work on the surroundings, so work is a negative quantity
finas
w = -PAV = -(1.00 atm)(4.5x10ʻ L – 4.0x10° L)E-5.0x10° L·atm
initigl change in volume
%3D
We must convert this value to Joules before we can subtract it from 1.3x10% J
Dividing the two values of the Gas Constant R gives us:
work = (-P)(AV)
%3D
8.3145 J/mole K/0.08206 L'atm/mole K= 101.322 J/L'atm
w = (-5.0x10 L'atm)(101.322 J/L•atm) = -5.07x107 J
%3D
%3D
AE = 1.3x108 J – 5.07x107 J = 7.93x107 J
%3D
8.31453/mate V
b
= 101.323/om
O.08206L•am
/mble h
-5.0x10°-atm
101.322y
-5.07x10
%3D
1
Page 1 of 5
Transcribed Image Text:Cnarge inheat sotemexpands aheatadded 3. A balloon is inflated to its full extent by(heating, The volume of the balloon changes from 4.0x106 liters to 4.5x10° liters by the addition of 1.3x10 Joules of energy as heat. Calculate the change in internal energy, AE, for the process (assume the balloon expands at constant pressure of 1.00 atm). {Hint: R = 0.08206 L·atm/mole-K = 8.3145 J/mole K} gasconstant Change inheak gasconstant %3D %3D for youles AE = q + w = heat + work Because heat is added, the internal energy of the system increases and q = +1.3x10 J %3D The system expands and does work on the surroundings, so work is a negative quantity finas w = -PAV = -(1.00 atm)(4.5x10ʻ L – 4.0x10° L)E-5.0x10° L·atm initigl change in volume %3D We must convert this value to Joules before we can subtract it from 1.3x10% J Dividing the two values of the Gas Constant R gives us: work = (-P)(AV) %3D 8.3145 J/mole K/0.08206 L'atm/mole K= 101.322 J/L'atm w = (-5.0x10 L'atm)(101.322 J/L•atm) = -5.07x107 J %3D %3D AE = 1.3x108 J – 5.07x107 J = 7.93x107 J %3D 8.31453/mate V b = 101.323/om O.08206L•am /mble h -5.0x10°-atm 101.322y -5.07x10 %3D 1 Page 1 of 5
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