For this problem, I was wondering where the 0.15 for the dead load and where the 0.04 came from the live load. If there is any conversion that happens in order to get those dead load and live load values, can you please show them
For this problem, I was wondering where the 0.15 for the dead load and where the 0.04 came from the live load. If there is any conversion that happens in order to get those dead load and live load values, can you please show them
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
For this problem, I was wondering where the 0.15 for the dead load and where the 0.04 came from the live load. If there is any conversion that happens in order to get those dead load and live load values, can you please show them?

Transcribed Image Text:2-3. The floor system used in a school classroom consists of a
4-in. reinforced stone concrete slab. Sketch the loading that
acts along the joist BF and side girder ABCDE. Set
a = 10 ft, b = 30 ft. Hint: See Tables 1.2 and 1.4.
SOLUTION
30 ft
Joist BF. Since
= 3, the concrete slab will behave as a one-way slab.
10 ft
Thus, the tributary area for this joist is the rectangular area shown in Fig. a, and the
intensity of the uniform distributed load is
b
a
4
1²³) (1/2) (10
-ft (10 ft) = 0.5 k/ft
4-in.-thick reinforced stone concrete slab: (0.15 k/ft³)
Live load for classroom: (0.04 k/ft²)(10 ft) = 0.4 k/ft
0.9 k/ft
Ans.
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