For the zero-order decomposition of HI on a gold surface HI (g) →Au1/2 H2 (g) + 1/2 I2(g) it takes 16.0 s for the pressure of HI to drop from 1.00 atm to 0.200 atm. (a) What is the rate constant for the reaction?(b) How long will it take for the pressure to drop from 0.150 atm to 0.0432 atm?(c) What is the half-life of HI at a pressure of 0.500 atm?
For the zero-order decomposition of HI on a gold surface HI (g) →Au1/2 H2 (g) + 1/2 I2(g) it takes 16.0 s for the pressure of HI to drop from 1.00 atm to 0.200 atm. (a) What is the rate constant for the reaction?(b) How long will it take for the pressure to drop from 0.150 atm to 0.0432 atm?(c) What is the half-life of HI at a pressure of 0.500 atm?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For the zero-order decomposition of HI on a gold surface
HI (g) →Au1/2 H2 (g) + 1/2 I2(g) it takes 16.0 s for the pressure of HI to drop from 1.00 atm to 0.200 atm.
(a) What is the rate constant for the reaction?
(b) How long will it take for the pressure to drop from 0.150 atm to 0.0432 atm?
(c) What is the half-life of HI at a pressure of 0.500 atm?
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