For the underdamped circuit shown in Fig. P7.110, determine the voltage v(t) if the initial conditions on the storage elements are iL(0) = 4 A and vc(0) = 20 V. i₁(0) 2 H + (1) Σ5Ω Figure P7.110 v(t) = e 2[20cos(4t) - 120sin(4t)] V v(t) = e4[cos(2t) + 120sin(2t)] V v(t) = e 4t[120cos(2t) - 20sin(2t)] V v(t)=e4[20cos(2t) - 120sin(2t)] V 40 + vc(0) -
For the underdamped circuit shown in Fig. P7.110, determine the voltage v(t) if the initial conditions on the storage elements are iL(0) = 4 A and vc(0) = 20 V. i₁(0) 2 H + (1) Σ5Ω Figure P7.110 v(t) = e 2[20cos(4t) - 120sin(4t)] V v(t) = e4[cos(2t) + 120sin(2t)] V v(t) = e 4t[120cos(2t) - 20sin(2t)] V v(t)=e4[20cos(2t) - 120sin(2t)] V 40 + vc(0) -
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![For the underdamped circuit shown in Figure P7.110, determine the voltage \( v(t) \) if the initial conditions on the storage elements are \( i_L(0) = 4 \, \text{A} \) and \( v_C(0) = 20 \, \text{V} \).
**Figure P7.110:**
The diagram shows a series RLC circuit:
- An inductor with an inductance of \( 2 \, \text{H} \) on the left, with initial current \( i_L(0) = 4 \, \text{A} \).
- A resistor of \( 5 \, \Omega \) in the middle.
- A capacitor with capacitance \( \frac{1}{40} \, \text{F} \) on the right, with initial voltage \( v_C(0) = 20 \, \text{V} \).
The circuit is grounded at the bottom node.
**Possible Solutions for \( v(t) \):**
- \( v(t) = e^{-2t}[20\cos(4t) - 120\sin(4t)] \, \text{V} \)
- \( v(t) = e^{-4t}[\cos(2t) + 120\sin(2t)] \, \text{V} \)
- \( v(t) = e^{-4t}[120\cos(2t) - 20\sin(2t)] \, \text{V} \)
- \( v(t) = e^{-4t}[20\cos(2t) - 120\sin(2t)] \, \text{V} \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0ab47578-81e4-46a2-abcb-43bbb3318efe%2Fb50aa183-206d-4baf-b3ca-eb1a892800ef%2Fh939fd7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For the underdamped circuit shown in Figure P7.110, determine the voltage \( v(t) \) if the initial conditions on the storage elements are \( i_L(0) = 4 \, \text{A} \) and \( v_C(0) = 20 \, \text{V} \).
**Figure P7.110:**
The diagram shows a series RLC circuit:
- An inductor with an inductance of \( 2 \, \text{H} \) on the left, with initial current \( i_L(0) = 4 \, \text{A} \).
- A resistor of \( 5 \, \Omega \) in the middle.
- A capacitor with capacitance \( \frac{1}{40} \, \text{F} \) on the right, with initial voltage \( v_C(0) = 20 \, \text{V} \).
The circuit is grounded at the bottom node.
**Possible Solutions for \( v(t) \):**
- \( v(t) = e^{-2t}[20\cos(4t) - 120\sin(4t)] \, \text{V} \)
- \( v(t) = e^{-4t}[\cos(2t) + 120\sin(2t)] \, \text{V} \)
- \( v(t) = e^{-4t}[120\cos(2t) - 20\sin(2t)] \, \text{V} \)
- \( v(t) = e^{-4t}[20\cos(2t) - 120\sin(2t)] \, \text{V} \)
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