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For the soil sample given below, the name of it should be Laccording to plasticity chart: LL = 8 PL = 7.9 O Pl=0.10 Inorganic silts of low compressibility O Pl=0.10 Inorganic clays of medium plasticity O Pl=0.10 Inorganic silts of medium compressibility and organic silts O Pl=0.10 Inorganic clays of low plasticity O Pl=0.10 Inorganic silts of high compressibility and organic clays O Pl=0.10 Inorganic clays of high plasticity O Pl=0.10 Cohesionless soil

For the soil sample given below, the name of it should be Laccording to plasticity chart: LL = 8 PL = 7.9 O Pl=0.10 Inorganic silts of low compressibility O Pl=0.10 Inorganic clays of medium plasticity O Pl=0.10 Inorganic silts of medium compressibility and organic silts O Pl=0.10 Inorganic clays of low plasticity O Pl=0.10 Inorganic silts of high compressibility and organic clays O Pl=0.10 Inorganic clays of high plasticity O Pl=0.10 Cohesionless soil

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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For the soil sample given below, the name of it should be Laccording to plasticity chart: LL = 8 PL = 7.9 O Pl=0.10 Inorganic silts of low compressibility O Pl=0.10 Inorganic clays of medium plasticity O Pl=0.10 Inorganic silts of medium compressibility and organic silts O Pl=0.10 Inorganic clays of low plasticity O Pl=0.10 Inorganic silts of high compressibility and organic clays O Pl=0.10 Inorganic clays of high plasticity O Pl=0.10 Cohesionless soil
Transcribed Image Text:For the soil sample given below, the name of it should be Laccording to plasticity chart: LL = 8 PL = 7.9 O Pl=0.10 Inorganic silts of low compressibility O Pl=0.10 Inorganic clays of medium plasticity O Pl=0.10 Inorganic silts of medium compressibility and organic silts O Pl=0.10 Inorganic clays of low plasticity O Pl=0.10 Inorganic silts of high compressibility and organic clays O Pl=0.10 Inorganic clays of high plasticity O Pl=0.10 Cohesionless soil
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