For the situation in Part F, find the magnitude of the force F (in kg. m/s²) necessary to make the block move. ► View Available Hint(s) F = VO ΑΣΦ ? kg. m/s²

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Chapter1: Units, Trigonometry. And Vectors
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Part F - Example: Finding Two Forces (Part I)
Two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. The block in (Figure 1) has a mass m = 10 kg and is being pulled
by a force F on a table with coefficient of static friction μ = 0.3. Four forces act on it:
• The applied force F (directed 0: 30° above the horizontal).
• The force of gravity Fg = mg (directly down, where g = 9.8 m/s²).
• The normal force N (directly up).
• The force of static friction fs (directly left, opposing any potential motion).
If we want to find the size of the force necessary to just barely overcome static friction (in which case fs = μs N), we use the condition that the sum of the forces in both directions must be 0. Using
some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as:
●
F cos 0 μs N=0
F sin 0+N-mg = 0
In order to find the magnitude of force F, we have to solve a system of two equations with both F and the normal force N unknown. Use the methods we have learned to find an expression for Fin
terms of m, g, 0, and μs (no N).
Express your answer in terms of m, g, 0, and µs .
View Available Hint(s)
F =
μg mg
cose+μ, sine
Submit
Previous Answers
Correct
Transcribed Image Text:Part F - Example: Finding Two Forces (Part I) Two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. The block in (Figure 1) has a mass m = 10 kg and is being pulled by a force F on a table with coefficient of static friction μ = 0.3. Four forces act on it: • The applied force F (directed 0: 30° above the horizontal). • The force of gravity Fg = mg (directly down, where g = 9.8 m/s²). • The normal force N (directly up). • The force of static friction fs (directly left, opposing any potential motion). If we want to find the size of the force necessary to just barely overcome static friction (in which case fs = μs N), we use the condition that the sum of the forces in both directions must be 0. Using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: ● F cos 0 μs N=0 F sin 0+N-mg = 0 In order to find the magnitude of force F, we have to solve a system of two equations with both F and the normal force N unknown. Use the methods we have learned to find an expression for Fin terms of m, g, 0, and μs (no N). Express your answer in terms of m, g, 0, and µs . View Available Hint(s) F = μg mg cose+μ, sine Submit Previous Answers Correct
Part G - Example: Finding Two Forces (Part II)
For the situation in Part F, find the magnitude of the force F (in kg · m/s²) necessary to make the block move.
► View Available Hint(s)
F =
Submit
VE ΑΣΦ
?
kg m/s²
Transcribed Image Text:Part G - Example: Finding Two Forces (Part II) For the situation in Part F, find the magnitude of the force F (in kg · m/s²) necessary to make the block move. ► View Available Hint(s) F = Submit VE ΑΣΦ ? kg m/s²
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