For the set of following data (C-reactive protein (CPR) measured for 40 children):0.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.003.493.93.924.815.365.535.625.645.666.817.17.898.229.379.5712.3815.7420.7822.8226.4130.6146.759.7673.2a)Find the five-number summary for these datab)Make a boxplotc)Make a histogram (use 8 classes)d)Find the mean and standard deviation (use a calculator)Write a short summary of the major features of this distribution.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Listed below are the lead concentrations in muμg/g measured in different traditional medicines. Use a 0.010.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 1717 muμg/g. Assume that the lead concentrations in traditional medicines are normally distributed. 1010 13.513.5 16.516.5 19.519.5 2121 13.513.5 3.53.5 22.522.5 1313 3.53.5 What are the null and alternative hypotheses? A. Upper H 0H0: muμequals=1717 muμg/g Upper H 1H1: muμless than<1717 muμg/g B. Upper H 0H0: muμequals=1717 muμg/g Upper H 1H1: muμgreater than>1717 muμg/g C. Upper H 0H0: muμequals=1717 muμg/g Upper H 1H1: muμnot equals≠1717 muμg/g D. Upper H 0H0: muμgreater than>1717 muμg/g Upper H 1H1: muμless than<1717 muμg/g Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to…
Find the area of the following z-scores using the z-table and draw the corresponding area under the standard normal curve on the space provided.
Create a histogram, and calculate x¯, the t-statistic, and the p-value. 34.0061858721506 43.35896389969 39.2839458791993 48.4458681201553 43.9450376906617 44.3387907086577 44.0113338310526 44.9349276905495 27.4460079151864 31.5475137945693 40.851809319706 54.4966548260204 51.2229130445186 26.5667263573046 43.8747602252099 63.6514039032307 46.348491340219 31.7043433858887 33.9291676728001 49.3914751882054 36.2727146960179 31.0702840945887 33.8717919763544 32.9018127450965 33.6820267911461 49.6234046401715 40.8105029866781 42.6603252306697 27.5886944329444 39.1727797888278 40.7544541502815 44.9921116882115 43.3559037906838 33.6109629249073 43.8720459237639 40.3090815090413 36.4897166851498 39.1530820200686 26.6401872184746 25.2436988903622 31.4427288953716 52.3131712579967 29.7246790933448 23.0352128112797 35.1500272627508 37.334025417453 29.509275714123 41.1197982416905 38.8772032697829…
Find the area to the right of the z-score 0.03 under the standard normal curve. z−0.2−0.10.00.10.000.42070.46020.50000.53980.010.41680.45620.50400.54380.020.41290.45220.50800.54780.030.40900.44830.51200.55170.040.40520.44430.51600.55570.050.40130.44040.51990.55960.060.39740.43640.52390.56360.070.39360.43250.52790.56750.080.38970.42860.53190.57140.090.38590.42470.53590.5753 Use the value(s) from the table above. Provide your answer below: FEEDBACK Content attribution- Opens a dialog
In a standard normal curve, what is the area between z = 0.27 and z = 2.03? O a. 37.24% O b. 47.88% O c. 10.64% O d. 58.52%
The following data (see photo) represent the weights (in grams) of random sample of 50 M&M plain candies. Determine the actual percentage of M&Ms that weigh more than 0.911 gram.
A researcher wanted to determine if using an octane booster would increase gasoline mileage. A random sample of seven cars was selected; the cars were driven for two weeks without the booster and two weeks with the booster.
Find the area under the standard normal curve that lies between the following: Z = -1.56 and Z = -0.56. Select one: a. 0.1587 O b. 0.2283 c. 0.3471 d. 0.8413
Determine the area under the standard normal curve that lies to the right of the z-score 0.28 and to the left of the z-score 0.43. 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -0.2 0.4207 0.4168 0.4129 0.4090 0.4052 0.4013 0.3974 0.3936 0.3897 0.3859 -0.1 0.4602 0.4562 0.4522 0.4483 0.4443 0.4404 0.4364 0.4325 0.4286 0.4247 0.0 0.5000 0.5040 0.5080 0.5120 0.5160 0.5199 0.5239 0.5279 0.5319 0.5359 0.1 0.5398 0.5438 0.5478 0.5517 0.5557 0.5596 0.5636 0.5675 0.5714 0.5753 0.2 0.5793 0.5832 0.5871 0.5910 0.5948 0.5987 0.6026 0.6064 0.6103 0.6141 0.3 0.6179 0.6217 0.6255 0.6293 0.6331 0.6368 0.6406 0.6443 0.6480 0.6517 0.4 0.6554 0.6591 0.6628 0.6664 0.6700 0.6736 0.6772 0.6808 0.6844 0.6879 0.5 0.6915 0.6950 0.6985 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.7224
7.88 Aluminum cans contaminated by fire. A gigantic NW warehouse located in Tampa, Florida, stores approxi- mately 60 million empty aluminum beer and soda cans. Recently, a fire occurred at the warehouse. The smoke from the fire contaminated many of the cans with black- spot, rendering them unusable. A University of South Florida statistician was hired by the insurance com- pany to estimate p, the true proportion of cans in the warehouse that were contaminated by the fire. How many aluminum cans should be randomly sampled to estimate the true proportion to within .02 with 90% confidence?
The amount of sodium (in milligrams) in one serving for a random sample of three different kinds of foods is listed. Find the critical value for testing for a difference in the mean sodium amounts at the a = 0.05 level of significance. Condiments Cereals 180 160 230 200 220 190 140 300 250 240 220 160 150 310 A) 3.05 B) 3.47 C) 0.33 D) 3.52 Desserts 340 130 280 230 210 150 340 120
Find the area to the right of the z-score 1.42 under the standard normal curve. z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 1.0 0.841 0.844 0.846 0.848 0.851 0.853 0.855 0.858 0.860 0.862 1.1 0.864 0.867 0.869 0.871 0.873 0.875 0.877 0.879 0.881 0.883 1.2 0.885 0.887 0.889 0.891 0.893 0.894 0.896 0.898 0.900 0.901 1.3 0.903 0.905 0.907 0.908 0.910 0.911 0.913 0.915 0.916 0.918 1.4 0.919 0.921 0.922 0.924 0.925 0.926 0.928 0.929 0.931 0.932 1.5 0.933 0.934 0.936 0.937 0.938 0.939 0.941 0.942 0.943 0.944 1.6 0.945 0.946 0.947 0.948 0.949 0.951 0.952 0.953 0.954 0.954 1.7 0.955 0.956 0.957 0.958 0.959 0.960 0.961 0.962 0.962 0.963 1.8 0.964 0.965 0.966 0.966 0.967 0.968 0.969 0.969 0.970 0.971 Use the value(s) from the table above. Round your answer to three decimal pla

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