For the Renantiomer of the molecule, the specific optical rotation is: [a]=+92°g1.cm3.dm 1 A solution containing a mixture of the 2 enantiomers, with a concentration of O.1 g.cm 3, is placed in a 10 cm tank and is analyzed in a polarimeter. The angle of deviation read is -5.52°. Using Biot's law, give the percentage of R enantiomer contained in this mixture. (result in percent, example answer 76)

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For the R enantiomer of the molecule, the specific optical rotation is : [a]=+92°.g1.cm³.dm1
A solution containing a mixture of the 2 enantiomers, with a concentration of 0.1 g.cm3, is placed in a 10 cm tank and is
analyzed in a polarimeter. The angle of deviation read is -5.52°.
Using Biot's law, give the percentage of R enantiomer contained in this mixture. (result in percent, example answer 76)
Transcribed Image Text:For the R enantiomer of the molecule, the specific optical rotation is : [a]=+92°.g1.cm³.dm1 A solution containing a mixture of the 2 enantiomers, with a concentration of 0.1 g.cm3, is placed in a 10 cm tank and is analyzed in a polarimeter. The angle of deviation read is -5.52°. Using Biot's law, give the percentage of R enantiomer contained in this mixture. (result in percent, example answer 76)
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