Give the correct stereochemistry at the chiral center of the following molecule: OR OIIII... ~

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:**

Give the correct stereochemistry at the chiral center of the following molecule:

**Diagram Description:**

The image shows a molecule with a carbon chain, including a double bond (alkene) and a chlorine (Cl) atom attached with a wedge, indicating a chiral center. The chiral center is bonded to a chlorine atom, and there is a sequence of carbon atoms forming the structure.

**Options:**

- R
- S

**Explanation:**

In this exercise, you are asked to determine the stereochemistry (R or S configuration) at the chiral center of the provided molecule. The wedge bond indicates that the chlorine atom is positioned out of the plane of the paper towards the viewer, which will affect the priority rules for determining configuration.
Transcribed Image Text:**Question:** Give the correct stereochemistry at the chiral center of the following molecule: **Diagram Description:** The image shows a molecule with a carbon chain, including a double bond (alkene) and a chlorine (Cl) atom attached with a wedge, indicating a chiral center. The chiral center is bonded to a chlorine atom, and there is a sequence of carbon atoms forming the structure. **Options:** - R - S **Explanation:** In this exercise, you are asked to determine the stereochemistry (R or S configuration) at the chiral center of the provided molecule. The wedge bond indicates that the chlorine atom is positioned out of the plane of the paper towards the viewer, which will affect the priority rules for determining configuration.
Expert Solution
Step 1

If the four atom attached to the chiral centre are all different priority depend on atomic number ,with the atom of high atomic number getting high priority.   If fourth group is below the plane then clock wise rotation gives R configuration and anticlockwise rotation gives S configuration.   If 4th group is above the plane then clockwise movement gives S configuration and anticlockwise movement gives Rconfiguration

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