For the reactionНСНО(9) + оз (9) —> СО:(9) + HаО(9)the value of AG° is –618.8 kJ/mol at 25°C. Other data are as follows:Substance AH; (kJ/mol) S° (J/(mol · K))НСНО-117.0219.0CO2-393.5213.7H2O-241.8188.7Оз142.7Calculate the entropy, S°, per mole of O3 (g).S°| J/(mol · K)Submit AnswerTry Another Version10 item attempts remaining

First we need to calculate ∆H° value from the given data. Followed by we will use ∆S° using…

For the reaction НСНО(9) + оз (9) —> СО»(9) + Hә0() 2. the value of AG° is –618.8 kJ/mol at 25°C. Other data are as follows: Substance AH; (kJ/mol) S° (J/(mol · K)) НСНО -117.0 219.0 CO2 -393.5 213.7 H20 -241.8 188.7 Оз 142.7 Calculate the entropy, S°, per mole of O3 (g). S° J/(mol · K)

For the reaction НСНО(9) + оз (9) —> СО»(9) + Hә0() 2. the value of AG° is –618.8 kJ/mol at 25°C. Other data are as follows: Substance AH; (kJ/mol) S° (J/(mol · K)) НСНО -117.0 219.0 CO2 -393.5 213.7 H20 -241.8 188.7 Оз 142.7 Calculate the entropy, S°, per mole of O3 (g). S° J/(mol · K)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the reaction 6CO2(g) + 6H20((1) C,H12O6 + 602(g) for which AH° = 2.801×10° kJ and AS° = -259.0 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.722 moles of CO2(g) react under standard conditions at 298.15 K. ASuniverse J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'.
For the reaction 2NH3(g) + 202(g)→N20(g) + 3H20(1) AH° = -683 kJ and AS° = -366 J/K !! AG would be less than zero at temperatures (above, below) К. Enter above or below in the first box and enter the temperature in the second box. Assume that AH° and AS° are constant.
The decomposition of copper (1) oxide to its elements does not occur spontaneously at 375°C (AG = 140.0 kJ): Cu₂0 (s) 2 Cu (s) + 1/2O₂(g). It can be made to occur spontaneously by being coupled to the oxidation of solid carbon to form carbon monoxide gas at this same temperature (AG = -143.8 kJ): C(s) + 1/2O₂(g) → CO (g) What product(s) is/are produced as a result of coupling the two reactions? CO (g) 2 Cu (s) and 1/2 O₂ (g) 2 Cu (s) and CO (g) 2 Cu (s), 1/2 O2 (g), and CO (g) 1/2 0₂ (g)
Use the data given here to calculate the values of AGan at 25 °C for the Compound AG; (kJ/mol) reaction described by the equation A +387.7 В +596.8 A + B =C +402.0 AGAN kJ
A mole of sodium met is added to water How much work is done on the atmosphere by the subsequent reaction if the temperature is 25 C°
"M" represents a metallic element. "X" represents a nonmetallic element. Calculate ΔH for the process M3X4(s) ⟶ 3M(s) + 2X2(g) from the following information: M(s) + ½X2(g) ⟶ MX(s) ΔH°= -286.2 kJ 3MX(s) + ½X2(g) ⟶ M3X4(s) ΔH°= -84.3 kJ
Using the values in the table below, calculate AGxn at 375 K for the reaction: 3 CO g) + 4 NH3(g) → 3 CH3OH(g) + 2 N2(g) AH°F, kJ/mol AG°, kJ/mol S°, J/mol K COg) CH3OH(g) CH3OH NH3(aq) NH3(g) N2(9) -111 -137 198 -201 -162 238 -239 -166 127 -80 -27 111 -46 -17 193 192 +55 +15 -7 +100,414 +150
Given the information AS = 302.0 J/K AS = -153.0 J/K А +В — 2D AH = 699.7 kJ С — D AH' = 398.0 kJ calculate AG at 298 K for the reaction A +B → 20 AG" = kJ
O-234 kJ 234 kJ -150. kJ -117 kJ Given: -1835kJ AH°, AHᵒf (kJ/mol) -941 -840 QUESTION 12 Use the standard reaction enthalpies given below to determine AH°rxn for the following reaction: P4(g) + 10 Cl₂(g) → 4 PC|5(s) PC15(s) → PC13(g) + Cl₂(g) P4(g) + 6 Cl₂(g) → 4 PCl3(g) rxn IF7(g) IF 5(9) 2(g) 62.42 = ? ΔΗ° rxn AH°rxn = +157 kJ = -1207 KJ QUESTION 13 Use the AH°f and AH°rxn information provided to calculate AH°f for IF: IF7(9) + 12(g) → IF5(g) + 2 IF(g) AH°rxn = -89 kJ
For the reaction C(s,graphite) + 02(g) CO2(g) AG° = -394.3 kJ and AS° = 2.9 J/K at 290 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 290 K. The standard enthalpy change for the reaction of 2.38 moles of C(s,graphite) at this temperature would be kJ.