O-234 kJ234 kJ-150. kJ-117 kJGiven:-1835kJAH°,AHᵒf (kJ/mol)-941-840QUESTION 12Use the standard reaction enthalpies given below to determine AH°rxn for the following reaction:P4(g) + 10 Cl₂(g) → 4 PC|5(s)PC15(s) → PC13(g) + Cl₂(g)P4(g) + 6 Cl₂(g) → 4 PCl3(g)rxnIF7(g)IF 5(9)2(g) 62.42= ?ΔΗ°rxnAH°rxn= +157 kJ= -1207 KJQUESTION 13Use the AH°f and AH°rxn information provided to calculate AH°f for IF:IF7(9) + 12(g) → IF5(g) + 2 IF(g)AH°rxn = -89 kJ

Answered: Image /qna-images/answer/f9467141-240c-4d7d-817c-d6b8fe255877.jpg

234 KJ -150. KJ -117 kJ QUESTION 12 Use the standard reaction enthalpies given below to determine. AH°rxn for the following reaction: P4(g) + 10 Cl2(g) → 4 PC15(s) ΔΗ, = ? rxn PC15(s)→ PC13(g) + Cl₂(g) P4(g) + 6 Cl₂(g) → 4 PC13(9) Given: -1835kJ AH°f (kJ/mol) -941 -840 QUESTION 13 Use the AH°f and AH°rxn information provided to calculate AH°f for IF: AH rxn IF7(g) + 12(g) → IF5(g) + 2 IF(g) IF7(g) IF 5(9) 12(g) 62.42 AHⓇ rxn AHⓇ = -1207 KJ rxn 1 = +157 kJ = -89 kJ

234 KJ -150. KJ -117 kJ QUESTION 12 Use the standard reaction enthalpies given below to determine. AH°rxn for the following reaction: P4(g) + 10 Cl2(g) → 4 PC15(s) ΔΗ, = ? rxn PC15(s)→ PC13(g) + Cl₂(g) P4(g) + 6 Cl₂(g) → 4 PC13(9) Given: -1835kJ AH°f (kJ/mol) -941 -840 QUESTION 13 Use the AH°f and AH°rxn information provided to calculate AH°f for IF: AH rxn IF7(g) + 12(g) → IF5(g) + 2 IF(g) IF7(g) IF 5(9) 12(g) 62.42 AHⓇ rxn AHⓇ = -1207 KJ rxn 1 = +157 kJ = -89 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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