For the reaction HCI(g) + NH3(g) NHẠCI(s) AG° = -98.0 kJ and AS° = -284.8 J/K at 274 K and 1 atm. This reaction is (reactant, product) | | favored under standard conditions at 274 K. The standard enthalpy change for the reaction of 2.09 moles of HCI(g) at this temperature would be kJ.
For the reaction HCI(g) + NH3(g) NHẠCI(s) AG° = -98.0 kJ and AS° = -284.8 J/K at 274 K and 1 atm. This reaction is (reactant, product) | | favored under standard conditions at 274 K. The standard enthalpy change for the reaction of 2.09 moles of HCI(g) at this temperature would be kJ.
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter15: Energy And Chemical Change
Section: Chapter Questions
Problem 98A
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![For the reaction
HCI(g) + NH3(g) → NHẠCI(s)
AG° = -98.0 kJ and AS° = -284.8 J/K at 274 K and 1 atm.
This reaction is (reactant, product)
| favored under standard conditions at 274 K.
The standard enthalpy change for the reaction of 2.09 moles of HCl(g) at this temperature would
be
kJ.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab9c6c64-11a9-4770-afb5-aa519577362f%2F9605f57b-ffe5-47e3-ac1b-c0d24ae6b03f%2F22al68a_processed.png&w=3840&q=75)
Transcribed Image Text:For the reaction
HCI(g) + NH3(g) → NHẠCI(s)
AG° = -98.0 kJ and AS° = -284.8 J/K at 274 K and 1 atm.
This reaction is (reactant, product)
| favored under standard conditions at 274 K.
The standard enthalpy change for the reaction of 2.09 moles of HCl(g) at this temperature would
be
kJ.
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