For the reaction, calculate how many grams of the product form when 21.4 g of Ca completely reacts. Assume that there is more than enough of the other reactant. Ca (s) + Cl2 (9) → CaCl2 (s) ANSWER: mCaCl2 %3D g rt B For the reaction, calculate how many grams of the product form when 21.4 g of Br2 completely reacts. Assume that there is more than enough of the other reactant. 2 K (s) + Br2 (1) - 2 KBr (s). ANSWER: mKBr = g

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Exercise 8.36: Problems - Mass-to-Mass Conversions
Part A
For the reaction, calculate how many grams of the product form when 21.4 g of Ca completely reacts.
Assume that there is more than enough of the other reactant.
Ca (s) + Cl2 (g) → CaCl2 (s)
ANSWER:
%3D
mCaCl2
Part B
For the reaction, calculate how many grams of the product form when 21.4 g of Br2 completely reacts.
Assume that there is more than enough of the other reactant.
2 K (s) + Br2 (1) →2 KBr (s)
ANSWER:
MKB.
%3D
Part C
For the reaction, calculate how many grams of the product form when 21.4 g of O2 completely reacts.
Assume that there is more than enough of the other reactant.
4 Cr (s) + 3 O2 (g) → 2 Cr2 O3 (s)
ANSWER:
%3D
mCr2O3
For the reaction, calculate how many grams of the product form when 21.4 g of Sr completely reacts.
Assume that there is more than enough of the other reactant.
2 Sr (s) + O2 (g) 2 SrO (s)
Part D
ANSWER:
mSro =
Exercise 8.66: Problems - Limiting Reactant, Theoretical Yield, and Percent Yield
Transcribed Image Text:Exercise 8.36: Problems - Mass-to-Mass Conversions Part A For the reaction, calculate how many grams of the product form when 21.4 g of Ca completely reacts. Assume that there is more than enough of the other reactant. Ca (s) + Cl2 (g) → CaCl2 (s) ANSWER: %3D mCaCl2 Part B For the reaction, calculate how many grams of the product form when 21.4 g of Br2 completely reacts. Assume that there is more than enough of the other reactant. 2 K (s) + Br2 (1) →2 KBr (s) ANSWER: MKB. %3D Part C For the reaction, calculate how many grams of the product form when 21.4 g of O2 completely reacts. Assume that there is more than enough of the other reactant. 4 Cr (s) + 3 O2 (g) → 2 Cr2 O3 (s) ANSWER: %3D mCr2O3 For the reaction, calculate how many grams of the product form when 21.4 g of Sr completely reacts. Assume that there is more than enough of the other reactant. 2 Sr (s) + O2 (g) 2 SrO (s) Part D ANSWER: mSro = Exercise 8.66: Problems - Limiting Reactant, Theoretical Yield, and Percent Yield
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