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For the reaction C + 2H2 → CH4, how many moles of hydrogen are needed to make 170.6 grams of methane, CH4? Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0 Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.: Element Molar Mass Hydrogen 1 Carbon 12

For the reaction C + 2H2 → CH4, how many moles of hydrogen are needed to make 170.6 grams of methane, CH4? Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0 Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.: Element Molar Mass Hydrogen 1 Carbon 12

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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## Chemistry Problem: Calculating Moles of Hydrogen Needed for Methane Production ### Problem Statement For the reaction \( \text{C} + 2\text{H}_2 \rightarrow \text{CH}_4 \), how many moles of hydrogen are needed to make 170.6 grams of methane, \( \text{CH}_4 \)? ### Instructions Round your answer to the nearest tenth. If your answer is a whole number like 4, report the answer as 4.0. ### Molar Masses Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect: | Element | Molar Mass | |----------|-------------| | Hydrogen | 1 | | Carbon | 12 | To solve this problem: 1. **Calculate the molar mass of methane \(\text{CH}_4\)** - Molar Mass of \(\text{CH}_4\) = (1 Carbon \(\times\) 12) + (4 Hydrogens \(\times\) 1) - Molar Mass of \(\text{CH}_4\) = 12 + 4 = 16 grams/mole 2. **Determine the number of moles of methane \( \text{CH}_4 \) in 170.6 grams** - Moles of \( \text{CH}_4 \) = \(\frac{170.6 \text{ grams}}{16 \text{ grams/mole}}\) - Moles of \( \text{CH}_4 \) = 10.6625 moles 3. **Using the stoichiometry of the reaction, find the moles of hydrogen \( \text{H}_2 \) needed** - According to the balanced equation \( \text{C} + 2\text{H}_2 \rightarrow \text{CH}_4 \), it takes 2 moles of \( \text{H}_2 \) to produce 1 mole of \( \text{CH}_4 \). - Moles of \( \text{H}_2 \) needed = 10.6625 moles \( \text{CH}_4 \) \(\times\) 2 moles \( \text{H}_2 \)/1 mole \( \text{CH}_4 \) -
Transcribed Image Text:## Chemistry Problem: Calculating Moles of Hydrogen Needed for Methane Production ### Problem Statement For the reaction \( \text{C} + 2\text{H}_2 \rightarrow \text{CH}_4 \), how many moles of hydrogen are needed to make 170.6 grams of methane, \( \text{CH}_4 \)? ### Instructions Round your answer to the nearest tenth. If your answer is a whole number like 4, report the answer as 4.0. ### Molar Masses Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect: | Element | Molar Mass | |----------|-------------| | Hydrogen | 1 | | Carbon | 12 | To solve this problem: 1. **Calculate the molar mass of methane \(\text{CH}_4\)** - Molar Mass of \(\text{CH}_4\) = (1 Carbon \(\times\) 12) + (4 Hydrogens \(\times\) 1) - Molar Mass of \(\text{CH}_4\) = 12 + 4 = 16 grams/mole 2. **Determine the number of moles of methane \( \text{CH}_4 \) in 170.6 grams** - Moles of \( \text{CH}_4 \) = \(\frac{170.6 \text{ grams}}{16 \text{ grams/mole}}\) - Moles of \( \text{CH}_4 \) = 10.6625 moles 3. **Using the stoichiometry of the reaction, find the moles of hydrogen \( \text{H}_2 \) needed** - According to the balanced equation \( \text{C} + 2\text{H}_2 \rightarrow \text{CH}_4 \), it takes 2 moles of \( \text{H}_2 \) to produce 1 mole of \( \text{CH}_4 \). - Moles of \( \text{H}_2 \) needed = 10.6625 moles \( \text{CH}_4 \) \(\times\) 2 moles \( \text{H}_2 \)/1 mole \( \text{CH}_4 \) -
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