3 Cu + 8HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H₂O In the above equation, how many grams of water can be made when 18.5 moles of HNO3 are consumed? Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0 Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.: Molar Element Mass Hydrogen 1 Nitrogen 14 Copper 63.5 Oxygen 16
3 Cu + 8HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H₂O In the above equation, how many grams of water can be made when 18.5 moles of HNO3 are consumed? Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0 Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.: Molar Element Mass Hydrogen 1 Nitrogen 14 Copper 63.5 Oxygen 16
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Stoichiometry Problem: Calculating Grams of Water
**Chemical Equation:**
\[ 3 \text{Cu} + 8 \text{HNO}_3 \rightarrow 3 \text{Cu(NO}_3\text{)}_2 + 2 \text{NO} + 4 \text{H}_2\text{O} \]
**Problem:**
In the above equation, how many grams of water can be made when 18.5 moles of \( \text{HNO}_3 \) are consumed?
**Instructions:**
Round your answer to the nearest tenth. If your answer is a whole number like 4, report the answer as 4.0.
**Molar Masses:**
Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.
| Element | Molar Mass |
|-----------|-------------|
| Hydrogen | 1 |
| Nitrogen | 14 |
| Copper | 63.5 |
| Oxygen | 16 |
### Process:
1. **Identify the Mole Ratio:**
\[ 8 \text{ moles of HNO}_3 \rightarrow 4 \text{ moles of H}_2\text{O} \]
Therefore,
\[ 18.5 \text{ moles of HNO}_3 \rightarrow \left(18.5 \div 8\right) \times 4 \text{ moles of H}_2\text{O} \]
2. **Calculate Moles of Water:**
\[ \text{Moles of H}_2\text{O} = \left(\frac{18.5}{8}\right) \times 4 \]
\[ \text{Moles of H}_2\text{O} = 2.3125 \times 4 \]
\[ \text{Moles of H}_2\text{O} = 9.25 \]
3. **Calculate Grams of Water:**
The molar mass of water (\( \text{H}_2\text{O} \)):
\[ (2 \times 1) + 16 = 18 \text{ g/mol} \]
Total grams of water:
\[ 9.25 \text](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fee54b90d-e4d6-4f72-b48d-d71475e94862%2F540667f0-ebdb-4096-856a-e7582c0ec023%2Fjgxdld_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Stoichiometry Problem: Calculating Grams of Water
**Chemical Equation:**
\[ 3 \text{Cu} + 8 \text{HNO}_3 \rightarrow 3 \text{Cu(NO}_3\text{)}_2 + 2 \text{NO} + 4 \text{H}_2\text{O} \]
**Problem:**
In the above equation, how many grams of water can be made when 18.5 moles of \( \text{HNO}_3 \) are consumed?
**Instructions:**
Round your answer to the nearest tenth. If your answer is a whole number like 4, report the answer as 4.0.
**Molar Masses:**
Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.
| Element | Molar Mass |
|-----------|-------------|
| Hydrogen | 1 |
| Nitrogen | 14 |
| Copper | 63.5 |
| Oxygen | 16 |
### Process:
1. **Identify the Mole Ratio:**
\[ 8 \text{ moles of HNO}_3 \rightarrow 4 \text{ moles of H}_2\text{O} \]
Therefore,
\[ 18.5 \text{ moles of HNO}_3 \rightarrow \left(18.5 \div 8\right) \times 4 \text{ moles of H}_2\text{O} \]
2. **Calculate Moles of Water:**
\[ \text{Moles of H}_2\text{O} = \left(\frac{18.5}{8}\right) \times 4 \]
\[ \text{Moles of H}_2\text{O} = 2.3125 \times 4 \]
\[ \text{Moles of H}_2\text{O} = 9.25 \]
3. **Calculate Grams of Water:**
The molar mass of water (\( \text{H}_2\text{O} \)):
\[ (2 \times 1) + 16 = 18 \text{ g/mol} \]
Total grams of water:
\[ 9.25 \text
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