For the reaction 2A(g) B(g) + C(g) at 700 °C, Kc = 3.92×104. Calculate the number of moles of B present at equilibrium if 3.49 moles of A is heated to 700 °C in 8.48-L container. 0.00784 mol (Your answer) 0.396 mol 3.36 mol 9.24×10-4 mol 0.0665 mol (Correct answer)

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For the reaction:

\[ 2A(g) \rightleftharpoons B(g) + C(g) \]

at 700°C, \( K_c = 3.92 \times 10^{-4} \). Calculate the number of moles of B present at equilibrium if 3.49 moles of A is heated to 700°C in an 8.48-L container.

Options:

- **0.00784 mol** (Your answer)
- 0.396 mol
- 3.36 mol
- \( 9.24 \times 10^{-4} \) mol
- **0.0665 mol** (Correct answer)
Transcribed Image Text:For the reaction: \[ 2A(g) \rightleftharpoons B(g) + C(g) \] at 700°C, \( K_c = 3.92 \times 10^{-4} \). Calculate the number of moles of B present at equilibrium if 3.49 moles of A is heated to 700°C in an 8.48-L container. Options: - **0.00784 mol** (Your answer) - 0.396 mol - 3.36 mol - \( 9.24 \times 10^{-4} \) mol - **0.0665 mol** (Correct answer)
Expert Solution
Step 1: Interpretation of datas :

G i v e n space comma
R e c a t i o n space colon space 2 space A left parenthesis g right parenthesis space rightwards harpoon over leftwards harpoon B left parenthesis g right parenthesis space plus C left parenthesis g right parenthesis
K subscript c equals 3.92 cross times 10 to the power of negative 4 end exponent
O b j e c t i v e space colon
C a l c u l a t e space n u m b e r space o f space m o l e s space o f space B space p r e s e n t space a t space e q u i l i b r i u m.

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