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For the question and solution provided, i do not understand why gain is = R2/ R1+R2.   From the equation R2wc/ (R1+R2)wc +1   why do we ignore the +1? When omega = 0, H(0) = 0 when omega = infinity, H(infinity) = 1 shouldn't H(infinity) be equals 1 instead of 2/3 ?

For the question and solution provided, i do not understand why gain is = R2/ R1+R2.   From the equation R2wc/ (R1+R2)wc +1   why do we ignore the +1? When omega = 0, H(0) = 0 when omega = infinity, H(infinity) = 1 shouldn't H(infinity) be equals 1 instead of 2/3 ?

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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For the question and solution provided, i do not understand why gain is = R2/ R1+R2.  

From the equation R2wc/ (R1+R2)wc +1  

why do we ignore the +1?

When omega = 0, H(0) = 0

when omega = infinity, H(infinity) = 1

shouldn't H(infinity) be equals 1 instead of 2/3 ?

T8.1 : cutoff frequency 1. In the circuit below find the expression of the frequency response H and plot the corresponding Bode plot for R1=1N, R2=2N and C=lµF. Is it a high pass or a low pass filter? What is the gain in the pass-band? Find the -3dB cut-off frequency using the graph and by computing it. + R1 + Vout R2 Vị 53kHz gain 2/3 (or -3.5dB) high-pass Answer:
Transcribed Image Text:T8.1 : cutoff frequency 1. In the circuit below find the expression of the frequency response H and plot the corresponding Bode plot for R1=1N, R2=2N and C=lµF. Is it a high pass or a low pass filter? What is the gain in the pass-band? Find the -3dB cut-off frequency using the graph and by computing it. + R1 + Vout R2 Vị 53kHz gain 2/3 (or -3.5dB) high-pass Answer:
Vin Re in fregueny domain R, Ry We こ Vo Vin This is High pass fi lter. gain R, t Ry
Transcribed Image Text:Vin Re in fregueny domain R, Ry We こ Vo Vin This is High pass fi lter. gain R, t Ry
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