10 n es(1) Q4) Answer question related to circuit given Given Vs(t) = 15 cos(100t) V a) Write vs (t) in phasor form b) In Figure 4a, what is Z₁? c) In Figure 4a, what is Zc? Note: Figure 4b is equivalent of Figure 4a as follows: Figure 4b d) In Figure 4b, Z₁ = 10 , let Z₂ = Z₁ (found in part (b)), and let Z3= {1502 resistor in parallel with Zc (found in part (c))}. Find Z3 in polar form. Show work, box answer. e) Compute Zeq = Z₁ + Z₂ + Z3 in polar form. f) Compute current I in Figure 4b using V as value obtained in part (a) and Zeq obtained in part (e). Show all work, final answer should be in phasor form. Write units and box answer. 50 mH 15 01 (1) Figure 4a Z₁ 12(1) 1 mF Z₂

10 n es(1) Q4) Answer question related to circuit given Given Vs(t) = 15 cos(100t) V a) Write vs (t) in phasor form b) In Figure 4a, what is Z₁? c) In Figure 4a, what is Zc? Note: Figure 4b is equivalent of Figure 4a as follows: Figure 4b d) In Figure 4b, Z₁ = 10 , let Z₂ = Z₁ (found in part (b)), and let Z3= {1502 resistor in parallel with Zc (found in part (c))}. Find Z3 in polar form. Show work, box answer. e) Compute Zeq = Z₁ + Z₂ + Z3 in polar form. f) Compute current I in Figure 4b using V as value obtained in part (a) and Zeq obtained in part (e). Show all work, final answer should be in phasor form. Write units and box answer. 50 mH 15 01 (1) Figure 4a Z₁ 12(1) 1 mF Z₂

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

See similar textbooks

Similar questions

For the circuit shown in figure.Find: Zi Zo Ai re
From Figure 1 above find Rth (BC) a. 4.24 b. 8.55O c. 6.86O d. 5.56
2, Zs Z7 Solve for: Solve for: h.) S5 i.) P6 j.) Q7 Given: E = 1002 – 90 volts Z4 = 42450 Z1 = 1200 Z5 = 5453.13N Z2 = 2436.87N Z6 = 62 – 90N Z3 = 32 - 30N Z, = 72750
b) Analyse the principles of circuit theory as applied to the circuits illustrated in Figure 4b with sinusoidal sources, to explain the operation of the circuit by determining the phase angle, ZT, IT, IR, IL, P. V=120V, 50Hz R₂=3002 and L=106 H. Vo (t) Figure 4b R2 ww L eeeee Vs (t)
Please answer all subparts for like either dislike is ready.. Please all subparts in short... Please..
a) What is Routh Array2 b) How to find the number of roots on right side using the Routh Array?.
. For the circuit given in figure 6, find V_ ms and I_rms on R3. R, R3 ww 10 20 R4 R2 C 40 5Vp Figure 6 ww ww
the adjoining figure. This lamp can withstand a maximum voltage 3.0 v 0.4 9. Volt-ampere (V-I) charaeteristics of an incandescent lamp 16thd in and a maximum current 0.4 A. An infinite ladder network consisting a large number of these lamps is also shown in the figure given belo How much maximum voltage can be applied between the terminals A and B, so that no lamp gets damaged? (Use V5 = 2.2). Ans:x4.2V Hint: Curentin all bulls except first is
MAT LAB course
Using source transformation theorem, solve the current, I, and voltage, V, in Figure Q4. Assume that the operating frequency is 50HZ. 20 mH 1220° V V. 50' 4290 A (*)1045° V F Figure Q4
Which of the following statements are correct for the circuit below? Thanks to the capacitors I – C1 and C2, the voltage gain of the circuit increases. II – Capacitors C1 and C2 are coupling capacitors and provide an isolation function between AC and DC voltages in the circuit. Thanks to the III – RE resistor, the voltage gain of the circuit increases. Thanks to the IV – RE resistor, the stability of the circuit increases. The V – C3 Capacitor is a bypass capacitor and prevents the loss of voltage gain. Capacitor VI – C3 is a coupling capacitor and has no effect on the voltage gain in the circuit. VII – As the value of the source internal resistance Rs increases, the voltage gain decreases. VIII – The voltage gain decreases as the value of any RL load to be added to the circuit increases
R₁ =1292 Igc = 0.16A IDC = Problem #21) Determine the source current Ipc and the resistor voltage V4 as shown in the following circuit using the Reduce and Return Method if the source voltage is Vpc = 72 volts. R₂=402 R₁ =1552 R₁=4592 0.16 IDC =. V₁=. 2 (A) 36 (A) (V)