For the isomerization reaction: butane ⇌ isobutane Kp equals 25 at 500°C. If the initial pressures of butane and isobutane are 10. atm and 0.0 atm, respectively, what are the pressures of the two gases at equilibrium? (This is a 1:1 stoichiometry) P(butane) = 10 atm and P(isobutane) = 0.40 atm P(butane) = 0.40 atm and P(isobutane) = 10. atm P(butane) = 9.6 atm and P(isobutane) = 0.38 atm P(butane) = 0.38 atm and P(isobutane) = 9.6 atm
For the isomerization reaction: butane ⇌ isobutane Kp equals 25 at 500°C. If the initial pressures of butane and isobutane are 10. atm and 0.0 atm, respectively, what are the pressures of the two gases at equilibrium? (This is a 1:1 stoichiometry) P(butane) = 10 atm and P(isobutane) = 0.40 atm P(butane) = 0.40 atm and P(isobutane) = 10. atm P(butane) = 9.6 atm and P(isobutane) = 0.38 atm P(butane) = 0.38 atm and P(isobutane) = 9.6 atm
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For the isomerization reaction:
butane ⇌ isobutane
Kp equals 25 at 500°C. If the initial pressures of butane and isobutane are 10. atm and 0.0 atm, respectively, what are the pressures of the two gases at equilibrium? (This is a 1:1 stoichiometry)
P(butane) = 10 atm and P(isobutane) = 0.40 atm
P(butane) = 0.40 atm and P(isobutane) = 10. atm
P(butane) = 9.6 atm and P(isobutane) = 0.38 atm
P(butane) = 0.38 atm and P(isobutane) = 9.6 atm
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