For the galvanic (voltaic) cell Fe(s) + Mn² (aq) Fe²(aq) + Mn(s) (E° = 0.77 V at 25°C), what is [Fe] if [Mn²+] = 0.050 M and E = 0.78 V?

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Galvanic (Voltaic) Cell Question:**

*This problem is focused on the equilibrium and voltage conditions in a galvanic cell involving iron and manganese.*

**Question:**

For the galvanic (voltaic) cell:  
\[ \text{Fe(s)} + \text{Mn}^{2+}(aq) \rightarrow \text{Fe}^{2+}(aq) + \text{Mn(s)} \]  
(E° = 0.77 V at 25°C), what is \([\text{Fe}^{2+}]\) if \([\text{Mn}^{2+}] = 0.050 \, M\) and E = 0.78 V?

**Options:**

A) 0.023 M  
B) 0.034 M  
C) 0.11 M  
D) 0.68 M  
E) 9.2 M  

---

*This question assesses understanding of the Nernst equation and the concept of cell potential in electrochemistry.*
Transcribed Image Text:**Galvanic (Voltaic) Cell Question:** *This problem is focused on the equilibrium and voltage conditions in a galvanic cell involving iron and manganese.* **Question:** For the galvanic (voltaic) cell: \[ \text{Fe(s)} + \text{Mn}^{2+}(aq) \rightarrow \text{Fe}^{2+}(aq) + \text{Mn(s)} \] (E° = 0.77 V at 25°C), what is \([\text{Fe}^{2+}]\) if \([\text{Mn}^{2+}] = 0.050 \, M\) and E = 0.78 V? **Options:** A) 0.023 M B) 0.034 M C) 0.11 M D) 0.68 M E) 9.2 M --- *This question assesses understanding of the Nernst equation and the concept of cell potential in electrochemistry.*
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