For the galvanic (voltaic) cell Cd²+ (aq) + Fe(s)→→ Cd(s) + Fe²+ (aq) (E° = 0.0400 V), what is the ratio [Fe² ]/[Cd²+] when E = 0.002 V? Assume T is 298 K

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For the galvanic (voltaic) cell:

\[ \text{Cd}^{2+}(aq) + \text{Fe}(s) \rightarrow \text{Cd}(s) + \text{Fe}^{2+}(aq) \quad (E^0 = 0.0400 \, \text{V}) \]

What is the ratio \([\text{Fe}^{2+}]/[\text{Cd}^{2+}]\) when \(E = 0.002 \, \text{V}\)? Assume \(T\) is 298 K.
Transcribed Image Text:For the galvanic (voltaic) cell: \[ \text{Cd}^{2+}(aq) + \text{Fe}(s) \rightarrow \text{Cd}(s) + \text{Fe}^{2+}(aq) \quad (E^0 = 0.0400 \, \text{V}) \] What is the ratio \([\text{Fe}^{2+}]/[\text{Cd}^{2+}]\) when \(E = 0.002 \, \text{V}\)? Assume \(T\) is 298 K.
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