For the following questions do not include units in the answer. Consider 5.34 g ammonium sulfide (M.W. = 68.15 g/mole) reacting with 9.37 g of lead(II) nitrate (M.W. = 331.20 g/mole). a) What is the balanced equation. Use physical states, use parenthesis and spaces where appropriate, and use an equal sign instead of a reaction arrow. b) What is the limiting reactant? c) What is the theoretical yield (in grams) of the solid product (M.W. 239.30 g/mole)? (3 sig. figs.) d) If 4.37 g of solid material are obtained, what is the percent yield? (3 sig. figs.)

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Chapter1: Chemical Foundations
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Question 4

For the following questions do not include units in the answer.

Consider 5.34 g ammonium sulfide (M.W. = 68.15 g/mole) reacting with 9.37 g of lead(II) nitrate (M.W. = 331.20 g/mole).

a) What is the balanced equation? *Use physical states, use parenthesis and spaces where appropriate, and use an equal sign instead of a reaction arrow.*
   
   [Answer box]

b) What is the limiting reactant?
   
   [Answer box]

c) What is the theoretical yield (in grams) of the solid product (M.W. 239.30 g/mole)? *(3 sig. figs.)*
   
   [Answer box]

d) If 4.37 g of solid material are obtained, what is the percent yield? *(3 sig. figs.)*
   
   [Answer box]
Transcribed Image Text:Question 4 For the following questions do not include units in the answer. Consider 5.34 g ammonium sulfide (M.W. = 68.15 g/mole) reacting with 9.37 g of lead(II) nitrate (M.W. = 331.20 g/mole). a) What is the balanced equation? *Use physical states, use parenthesis and spaces where appropriate, and use an equal sign instead of a reaction arrow.* [Answer box] b) What is the limiting reactant? [Answer box] c) What is the theoretical yield (in grams) of the solid product (M.W. 239.30 g/mole)? *(3 sig. figs.)* [Answer box] d) If 4.37 g of solid material are obtained, what is the percent yield? *(3 sig. figs.)* [Answer box]
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