1. Write the correct chemical equation for the following reaction:when beryllium chloride reacts with silver (I) nitrate,beryllium nitrate and silver (I) chloride are formed 2. Write the correct skeleton equation for the following:fluorine gas reacts with calcium metal to formsolid calcium fluoride **Question:**Write the correct skeleton equation for the following: fluorine gas reacts with calcium metal to form solid calcium fluoride.**Answer:**To write the skeleton equation for this reaction, we need to represent the reactants and products with their chemical formulas.1. **Fluorine gas** is diatomic, so it's represented as \( \text{F}_2 \).2. **Calcium metal** is simply represented as \( \text{Ca} \).3. **Calcium fluoride** is represented as \( \text{CaF}_2 \).The skeleton equation for the reaction will be:\[ \text{Ca} + \text{F}_2 \rightarrow \text{CaF}_2 \]This equation shows that calcium metal reacts with fluorine gas to produce solid calcium fluoride. **Reaction of Beryllium Chloride with Silver (I) Nitrate**To write the correct chemical equation for the reaction described, we start with the reactants: beryllium chloride and silver (I) nitrate. These react to form the products: beryllium nitrate and silver (I) chloride.**Chemical Equation:**\[ \text{BeCl}_2 (aq) + 2 \text{AgNO}_3 (aq) \rightarrow \text{Be(NO}_3\text{)}_2 (aq) + 2 \text{AgCl} (s) \]**Explanation:**- **Reactants:** - Beryllium chloride (\(\text{BeCl}_2\)) is an aqueous solution. - Silver (I) nitrate (\(\text{AgNO}_3\)) is also in aqueous solution.- **Products:** - Beryllium nitrate (\(\text{Be(NO}_3\text{)}_2\)) remains in the aqueous phase. - Silver chloride (\(\text{AgCl}\)) forms as a solid precipitate.This reaction is an example of a double displacement reaction, where the cations and anions of the reactants exchange partners to form new compounds.

Answered: 1. Write the correct chemical equation…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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1. Write the correct chemical equation for the following reaction:

when beryllium chloride reacts with silver (I) nitrate,

beryllium nitrate and silver (I) chloride are formed

2. Write the correct skeleton equation for the following:

fluorine gas reacts with calcium metal to form

solid calcium fluoride

**Reaction of Beryllium Chloride with Silver (I) Nitrate**

To write the correct chemical equation for the reaction described, we start with the reactants: beryllium chloride and silver (I) nitrate. These react to form the products: beryllium nitrate and silver (I) chloride.

**Chemical Equation:**

\[ \text{BeCl}_2 (aq) + 2 \text{AgNO}_3 (aq) \rightarrow \text{Be(NO}_3\text{)}_2 (aq) + 2 \text{AgCl} (s) \]

**Explanation:**

- **Reactants:**
- Beryllium chloride (\(\text{BeCl}_2\)) is an aqueous solution.
- Silver (I) nitrate (\(\text{AgNO}_3\)) is also in aqueous solution.

- **Products:**
- Beryllium nitrate (\(\text{Be(NO}_3\text{)}_2\)) remains in the aqueous phase.
- Silver chloride (\(\text{AgCl}\)) forms as a solid precipitate.

This reaction is an example of a double displacement reaction, where the cations and anions of the reactants exchange partners to form new compounds.

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Correct skeleton equation of a reaction represents the reactants on the left and products on the right side, both are separated by an arrow. The numbers of atoms of each element and the total charge remain the same on both sides of the equation.

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