For the following main function int _tmain(int argc, _TCHAR* argv[]) { int years[10]={2007, 2008, 2009, 2010, 2011, 2012,2013, 2014, 2015, 2016}; cout<<"Years before updating: "<«endl; for(int i=0;i<10;i++) cout<<*(years+i)«"\t"; } cout<

For the following main function int _tmain(int argc, _TCHAR* argv[]) { int years[10]={2007, 2008, 2009, 2010, 2011, 2012,2013, 2014, 2015, 2016}; cout<<"Years before updating: "<«endl; for(int i=0;i<10;i++) cout<<*(years+i)«"\t"; } cout<

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Matrix.h #include <iostream>#include <iomanip>using namespace std; #ifndef MATRIX_H#define MATRIX_Hclass Matrix{ friend ostream& operator<<(ostream& out, const Matrix& srcMatrix);public: Matrix(); // initialize Matrix class object with rowN=1, colN=1, and zero value Matrix(const int rN,const int cN ); // initialize Matrix class object with row number rN, col number cN and zero values Matrix(const Matrix &srcMatrix ); // initialize Matrix class object with another Matrix class object Matrix(const int rN, const int cN, const float *srcPtr); // initialize Matrix class object with row number rN, col number cN and a pointer to an array const float * getData()const; // create a temp pointer and copy the array values which data pointer points, // then returns temp. int getRowN()const; // returns rowN int getColN()const; // returns colN void print()const; // prints the Matrix object in rowNxcolN form Matrix…
#include <iostream>#include <string>#include <cstdlib>using namespace std;template<class T>class A{public:A(){cout<<"Created\n";}~A(){cout<<"Destroyed\n";}}; int main(int argc, char const *argv[]){A <int>a1;A <char>a2;A <float>a3;return 0;} Give output for this code
Problem DNA: Subsequence markingA common task in dealing with DNA sequences is searching for particular substrings within longer DNA sequences. Write a function mark_dna that takes as parameters a DNA sequence to search, and a shorter target sequence to find within the longer sequence. Have this function return a new altered sequence that is the original sequence with all non-overlapping occurrences of the target surrounded with the characters >> and <<. Hints: ● String slicing is useful for looking at multiple characters at once. ● Remember that you cannot modify the original string directly, you’ll need to build a copy. Start with an empty string and concatenate onto it as you loop. Constraints: ● Don't use the built-in replace string method. All other string methods are permitted. >>> mark_dna('atgcgctagcatg', 'gcg') 'at>>gcg<<ctagcatg' >>> mark_dna('atgcgctagcatg', 'gc')…
Links Bing Remaining Time: 1 hour, 24 minutes, 17 seconds. * Question Completion Status: Р QUESTION 8 bbhosted.cuny.edu/webapps/assessment/take/launch.jsp?course_assessment_id=_2271631_1&course_id=_2 Implement the following: 1) Define a function evenList() with an arbitrary parameter a. P 2) This function accepts any number of integer arguments. 3) evenList() stores all even numbers into a list and returns the list. 4) Call the function with 5, 6, 7, 8, 9, 10 as arguments. 5) Print the result of the function call. Make sure to precisely match the output format below. Write your code in the ANSWER area provided below (must include comments if using code is not covered in the course). Example Output [6, 8, 10] For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph Arial QUESTION 9 Programs s 10pt Click Save and Submit to save and submit. Click Save All Answers to save all answers. く Ev Av
#include <iostream>#include <vector>using namespace std; void PrintVectors(vector<int> numsList) { unsigned int i; for (i = 0; i < numsList.size(); ++i) { cout << numsList.at(i) << " "; } cout << endl;} int main() { vector<int> numsList; int userInput; int i; for (i = 0; i < 3; ++i) { cin >> userInput; numsList.push_back(userInput); } numsList.erase(numsList.begin()+1); numsList.insert(numsList.begin()+1, 102); numsList.insert(numsList.begin()+1, 100); PrintVectors(numsList); return 0;} Not all tests passed clearTesting with inputs: 33 200 10 Output differs. See highlights below. Special character legend Your output 33 100 102 10 Expected output 100 33 102 10 clearTesting with inputs: 6 7 8 Output differs. See highlights below. Special character legend Your output 6 100 102 8 Expected output 100 6 102 8 Not sure what I did wrong but the the 33…
#include <iostream> #include <string> #include <cstdlib> using namespace std; template<class T> class A { public: T func(T a, T b){ return a/b; } }; int main(int argc, char const *argv[]) { A <float>a1; cout<<a1.func(3,2)<<endl; cout<<a1.func(3.0,2.0)<<endl; return 0; } Give output for this code.
int main(int argc, char **argv) { float *rainfall; float rain_today; // rainfall has been dynamically allocated space for a floating point number. // Both rainfall and rain today have been initialized in hidden code. // Assign the amount in rain_today to the space rainfall points to. return 0; }
C programming fill in the following code #include "graph.h" #include <stdio.h>#include <stdlib.h> /* initialise an empty graph *//* return pointer to initialised graph */Graph *init_graph(void){} /* release memory for graph */void free_graph(Graph *graph){} /* initialise a vertex *//* return pointer to initialised vertex */Vertex *init_vertex(int id){} /* release memory for initialised vertex */void free_vertex(Vertex *vertex){} /* initialise an edge. *//* return pointer to initialised edge. */Edge *init_edge(void){} /* release memory for initialised edge. */void free_edge(Edge *edge){} /* remove all edges from vertex with id from to vertex with id to from graph. */void remove_edge(Graph *graph, int from, int to){} /* remove all edges from vertex with specified id. */void remove_edges(Graph *graph, int id){} /* output all vertices and edges in graph. *//* each vertex in the graphs should be printed on a new line *//* each vertex should be printed in the following format:…