For the following function, find the Taylor series centered at x = T and then give the first 5 nonzero terms of the Taylor series and the open interval of convergence. f(x) = sin(x) f(x) (-1)^9n+1)(x-pi)^2n)/((2n)!) n=0 f(x) = ((x-pi)^2)/(2!) ((x-pi)^4)/(4!) +(x-pi)^6)/(6!) -1 ((x-pi)^8)/(8!) 十…… (Give your answer in interval notation.) The open interval of convergence is: (-inf, inf) .........................

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