Find a power series, centered at 2, for the function f(x) = 1 and the interval Зд — 2 on which the expression is valid. OA. 5(-1)"3"(x – 2)" 4n+1 i > x > O B. 3" (r – 2)" 4u+1 x > n=0 Oc. (-1)"3"(г — 2)" 4n+1 -} < z < ! n=0 -3"r" -} < z < { n=0 OE. -3"(л — 2)" -,{ < z < } 2n+1 n=0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 44RE
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Find a power series, centered at 2, for the function f(x) =
1
and the interval
3x – 2
on which the expression is valid.
OA.
5(-1)"3"(x – 2)"
4n+1
n=0
В.
3" (x – 2)"
4n+1
< x < 5
10
n=0
OC.
(-1)*3"(x – 2)"
4n+1
<z< !0
n=0
D.
-3"g"
Σ
,一号<a<
2n+1
n=0
E.
-3" (x – 2)"
2n+1
> 3
n=0
Transcribed Image Text:Find a power series, centered at 2, for the function f(x) = 1 and the interval 3x – 2 on which the expression is valid. OA. 5(-1)"3"(x – 2)" 4n+1 n=0 В. 3" (x – 2)" 4n+1 < x < 5 10 n=0 OC. (-1)*3"(x – 2)" 4n+1 <z< !0 n=0 D. -3"g" Σ ,一号<a< 2n+1 n=0 E. -3" (x – 2)" 2n+1 > 3 n=0
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